passing a pointer to float in array to a function accepting fixed size arrays

Question

I have a number of functions that have the following form:

typedef float arr3[3];
float newDistanceToLine(arr3 &p0, arr3 &p1, arr3 &p2);

and now find convenient to store lots of points into a long array:

int n_points = 14;
float *points;
points = new float[3*n_points];

Is there a way to pass pointers to different values of the array "points" to my functions accepting fixed size arrays? I know that the following fails, but, I would like to do something like:

newDistanceToLine(&points[3], &points[6], &points[9]);

or get any help on how best to reuse my code.

Thanks!

Use the standard library std::vector<std::array<float,3>>

StoryTeller - Unslander Monica
– StoryTeller - Unslander Monica

2016-11-24 12:38:20 +00:00
Commented Nov 24, 2016 at 12:38 — StoryTeller - Unslander Monica
– StoryTeller - Unslander Monica, Commented Nov 24, 2016 at 12:38

Community · Accepted Answer · 2017-05-23 12:24:33Z

3

Change interface of your newDistanceToLine to use type that is based on pattern that can be called either array_View or span - read this discussion.

Something like this:

typedef float arr3[3];
class arr3_view
{
public:
    arr3_view(arr3& arr) : data(arr) {}
    arr3_view(float* data, std::size_t size) : data(data) 
    {
        if (size != 3) // or < 3 - I am not sure what is better for your case
          throw std::runtime_error("arr3 - wrong size of data: " + std::to_string(size));
    }

    float* begin() { return data; }
    float* end() { return data + 3; }
    float& operator [](std::size_t i) { return data[i]; }
    // and similar stuff as above for const versions

private:
    float* data;
};

float newDistanceToLine(arr3_view p0, arr3_view p1, arr3_view p2);

So - for you 9-elements arrays we will have such usage:

newDistanceToLine(arr3_view(arr, 3), 
                  arr3_view(arr + 3, 3), 
                  arr3_view(arr + 6, 3));

edited May 23, 2017 at 12:24

CommunityBot

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answered Nov 24, 2016 at 12:54

PiotrNycz

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3 Comments

solernou Over a year ago

Lovely answer, PiotrNycz. I will be trying something like that. In terms of performance, do you think it is worth trying C++11 ` span `, or any other alternative?

PiotrNycz Over a year ago

There should be no performance penalty for span - it is just generalized (template) version of what I presented. But I rather guess this is not C++11 but some compiler/library extension - see this answer: quora.com/What-is-the-span-T-in-the-CppCoreGuidelines But if you have this span in your environment - then just use it...

solernou Over a year ago

Well, I just coded your approach, changed arr3& arr into arr3 (&arr) making it a bit more flexible, and templated it. It works beautifully!!

arturx64 · Accepted Answer · 2016-11-24 13:00:36Z

1

Use data structure instead.

struct SPosition
{
SPosition( float x = 0, float y = 0, float z = 0)
    :X(x)
    ,Y(y)
    ,Z(z)
{

}
float X;
float Y;
float Z;
};

std::vector<SPosition> m_positions;

float newDistanceToLine( const SPosition& pt1, const SPosition& pt2, const SPosition& pt3 )
{
    // to do
    return 0.f;
};

answered Nov 24, 2016 at 13:00

arturx64

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