9

I have an array:

var a = [2,3,4,5,5,4]

I want to get unique array out of given array like

b = [2,3,4,5]

I have tried 

a.filter(function(d){return b.indexOf(d)>-1})

and I don't want to use for loop.

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3

3 Answers 3

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14

You can simply do it in JavaScript, with the help of the second - index - parameter of the filter method:

var a = [2,3,4,5,5,4];
a.filter(function(value, index){ return a.indexOf(value) == index });
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3 Comments

I will be happy if u explain this "function(d,i){return a.indexOf(d)==i}"
i in parameter is for indexing , means when you check for second last 5 , index would be 4 but indexOf would be 3 so they dont match hence it wiill filter out
Thanks.You have given a simple,tricky and great answer to this problem
6

This is not an Angular related problem. It can be resolved in a couple of ways depending which libraries you are using.

If you are using jquery:

var uniqeElements = $.unique([2,3,4,5,5,4]);

The output would be:

[2,3,4,5]

If you are using underscore:

var uniqeElements = _.uniq([2,3,4,5,5,4]);

Same output.

And pure JS code:

var unique = [2,3,4,5,5,4].filter(function(elem, index, self) {
    return index == self.indexOf(elem);
})
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Comments

0 
var b = a.filter( function( item, index, inputArray ) {
       return inputArray.indexOf(item) == index;
});
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2 Comments

Please add some explanation to your code
Please Refer Yaser Adel Mehraban sloution

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