Why does numpy.ndarray.resize() return None

Question

I ran the following code in order to obtain a 2-by-3 array:

import numpy as np
a = np.arange(6).resize(2,3)
print(a)

However, the output is

None

Why is this? Many thanks

All operations in Python that operate in-place return None.

Daniel Roseman
– Daniel Roseman

2016-11-30 11:34:29 +00:00
Commented Nov 30, 2016 at 11:34 — Daniel Roseman
– Daniel Roseman, Commented Nov 30, 2016 at 11:34
Many thanks! This makes it clear.

Chao
– Chao

2016-11-30 11:42:53 +00:00
Commented Nov 30, 2016 at 11:42 — Chao
– Chao, Commented Nov 30, 2016 at 11:42

mozzafunk · Accepted Answer · 2016-11-30 11:34:55Z

4

What you want to do is

import numpy as np
a = np.arange(6).reshape((2,3))
print(a)

to use resize :

a = np.arange(6)
a = np.resize(a, (2,3))

answered Nov 30, 2016 at 11:34

mozzafunk

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3 Comments

Chao Over a year ago

reshape doesn't change the base content. But resize should return a new array which is with the requested dimension. Is this right? I just wondered why my code doesn't return a new array.

Chao Over a year ago

I just checked the reference. What ndarray.resize() returns is exactly None. Thank you for your comment.

mozzafunk Over a year ago

reshape need that the array have the same number of element. With resize, if the new array is larger than the original array, then the new array is filled with repeated copies of a.

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