I'm new to image processing and I'm really having a hard time understanding stuff...so the idea is that how do you create a matrix from a binary image in python?
to something like this:
It not the same image though the point is there. Thank you for helping, I appreciate it cheers
Using cv2 -Read more here
import cv2
img = cv2.imread('path/to/img.jpg')
resized = cv2.resize(img, (128, 128), cv2.INTER_LINEAR)
print pic
Using skimage - Read more here
import skimage.io as skio
faces = skio.imread_collection('path/to/images/*.pgm',conserve_memory=True) # can load multiple images at once
Using Scipy - Read more here
from scipy import misc
pic = misc.imread('path/to/img.jpg')
print pic
Plotting Images
import matplotlib.pyplot as plt
plt.imshow(faces[0],cmap=plt.cm.gray_r,interpolation="nearest")
plt.show()
"""
A set of utilities that are helpful for working with images. These are utilities
needed to actually apply the seam carving algorithm to images
"""
from PIL import Image
class Color:
"""
A simple class representing an RGB value.
"""
def __init__(self, r, g, b):
self.r = r
self.g = g
self.b = b
def __repr__(self):
return f'Color({self.r}, {self.g}, {self.b})'
def __str__(self):
return repr(self)
def read_image_into_array(filename):
"""
Read the given image into a 2D array of pixels. The result is an array,
where each element represents a row. Each row is an array, where each
element is a color.
See: Color
"""
img = Image.open(filename, 'r')
w, h = img.size
pixels = list(Color(*pixel) for pixel in img.getdata())
return [pixels[n:(n + w)] for n in range(0, w * h, w)]
def write_array_into_image(pixels, filename):
"""
Write the given 2D array of pixels into an image with the given filename.
The input pixels are represented as an array, where each element is a row.
Each row is an array, where each element is a color.
See: Color
"""
h = len(pixels)
w = len(pixels[0])
img = Image.new('RGB', (w, h))
output_pixels = img.load()
for y, row in enumerate(pixels):
for x, color in enumerate(row):
output_pixels[x, y] = (color.r, color.g, color.b)
img.save(filename)
