Invoke-WebRequest pass url as script argument (PowerShell)

Question

I am trying to download file from the web using following command

Invoke-WebRequest $url -OutFile $filePath -Headers $Headers

I have argument, which contains this url and it is passed as parameter

[string]$artifactHttpAddress = $args[2]

Currently its value is

http://10.45.48.26/httpAuth/repository/downloadAll/TeamCityTest_Build/529:id/artifacts.zip

So, when I try to invoke WebRequest with following command
Invoke-WebRequest $artifactHttpAddress -OutFile c:/test.zip -Headers $Headers

it is downloading empty zip file .

but when I try to assign this url to the variable and invoke web request

$url = "http://10.45.48.26/httpAuth/repository/downloadAll/TeamCityTest_Build/529:id/artifacts.zip"
Invoke-WebRequest  $url -OutFile   c:/test.zip  -Headers $Headers

It is working correctly, downloads zip file, which have some content in it.

I tried following script

Write-Host([string]$url -eq [string]$artifactHttpAddress) 
Write-Host([string]$url) 
Write-Host([string]$artifactHttpAddress)

It outputs

 False
 http://10.45.48.26/httpAuth/repository/downloadAll/TeamCityTest_Build/528:id/artifacts.zip
 http://10.45.48.26/httpAuth/repository/downloadAll/TeamCityTest_Build/531:id/artifacts.zip

What is happening and why?

p.s. this script is inside ScriptBlock

jj27 · Accepted Answer · 2016-12-02 16:58:15Z

2

It looks to me, based on your output, that $url and $artifactHttpAddress are not the same value. Does the ZIP file exist at the URL with 531 in it?

answered Dec 2, 2016 at 16:58

jj27

1785 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

bumbeishvili Over a year ago

That was issue I think, missed difference between urls

Collectives™ on Stack Overflow

Invoke-WebRequest pass url as script argument (PowerShell)

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related