check another script's output from within the script

Question

Here's my script:

#!/bin/bash

path=$1

if [[ ./first.sh "$path" == "0" ]]
     echo "0"
fi

The script "first.sh" prints a number using echo. Now in the second script i wanna check if the output of the first script was "0" and if so, print "0"

What am I doing wrong?

CDe · Accepted Answer · 2016-12-03 14:34:13Z

1

If you want to read the output of a command/script run in shell, wrap it in $(). For example variable=$(ls "$path") reads the output of ls for the given path into variable.

Applying this to your problem

#!/bin/bash

path=$1
output=$(./first.sh "$path")
if [[ "$output" == "0" ]]; then
     echo "0"
fi

Please note that i also removed some errors (use ; then after the if statement).

answered Dec 3, 2016 at 14:34

CDe

1816 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

UFC Insider Over a year ago

thanks! is it possible to do something like this: if [[ $(ls -d */ "$path") = ""]]; then ? i wanna check if the path has no subdirectories

CDe Over a year ago

If you want to see if there is subdirectories, you can use find. Its a very usefull utility (check man7.org/linux/man-pages/man1/find.1.html). find "$path" -maxdepth 0 -type d | wc -l will give you the number of subdirectories. This should be 1 in case its empty, because only . will be returned for empty dirs.

Collectives™ on Stack Overflow

check another script's output from within the script

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related