How to initialize a array with precompiler In C Programming Language

A couple of questions:

1. Have you defined the type U8 with something like typedef unsigned char U8;?
2. Have you defined LCD_LANGUAGE as either LANG_1 or LANG_2?

The reason I ask is because this little snippet below compiles and runs just fine:

#include <stdio.h>
typedef unsigned char U8;
#define LCD_LANGUAGE LANG_1
static const U8 userFont[8][8] =
{
#if (LCD_LANGUAGE == LANG_1)
    { 0x0E, 0x09, 0x09, 0x1D, 0x09, 0x09, 0x0E, 0x00 },
    { 0x03, 0x0E, 0x11, 0x10, 0x10, 0x11, 0x0E, 0x00 },
    { 0x09, 0x06, 0x0F, 0x01, 0x02, 0x04, 0x0F, 0x00 },
    { 0x0E, 0x11, 0x10, 0x10, 0x15, 0x0E, 0x04, 0x00 },
    { 0x11, 0x0E, 0x11, 0x10, 0x10, 0x11, 0x0E, 0x00 },
    { 0x19, 0x06, 0x09, 0x04, 0x02, 0x09, 0x06, 0x00 },
    { 0x00, 0x01, 0x01, 0x01, 0x01, 0x03, 0x03, 0x03 },
    { 0x03, 0x03, 0x03, 0x01, 0x01, 0x01, 0x01, 0x01 }
#elif (LCD_LANGUAGE == LANG_2)
    { 0x0A, 0x00, 0x11, 0x11, 0x11, 0x11, 0x0E, 0x00 },
    { 0x04, 0x00, 0x1E, 0x04, 0x04, 0x04, 0x1E, 0x00 },
    { 0x0A, 0x00, 0x0E, 0x11, 0x11, 0x11, 0x0E, 0x00 },
    { 0x0E, 0x11, 0x10, 0x10, 0x11, 0x0E, 0x04, 0x00 },
    { 0x0F, 0x10, 0x10, 0x0E, 0x01, 0x1E, 0x04, 0x00 },
    { 0x0E, 0x00, 0x0F, 0x10, 0x17, 0x11, 0x0F, 0x00 },
    { 0x01, 0x01, 0x01, 0x01, 0x01, 0x03, 0x03, 0x03 },
    { 0x03, 0x03, 0x03, 0x01, 0x01, 0x01, 0x01, 0x01 }
#endif
};
int main (void) {
    printf ("0x%02x 0x%02x\n", userFont[0][0], userFont[2][2]);
    return 0;
}

producing:

0x0e 0x0f

LANG_1 AND LANG_2 is enum so in procompile time this objects are invalid. So I replace wtih integral values my problem is solved. Thanks.