JavaScript Recursion with loop

Question

I'm using this with Node.JS This is the example code:

function test(x){
    this.x = x
    for (this.i = 0; this.i < 10; this.i++) {
        console.log(this.x + ' - ' + this.i)
        if (this.x < 3) {
            this.x++
            test(this.x)
        }
    }

}

test(0)

when execution hits test(this.x) it is exiting the for loop. Is there any way to kick off the function and not exit the for loop?

This code exports:

The desired output would be:

2 issues here: global context (this) and wrong place for recursive call(should be outside of loop) — vp_arth
– vp_arth, Commented Dec 5, 2016 at 21:03

idbehold · Accepted Answer · 2016-12-05 20:38:59Z

3

You just need to move the recursion out of the for-loop:

function test(x){
    for (var i = 0; i < 10; i++) {
        console.log(x + ' - ' + i)
    }
    if (x < 3) {
        test(x + 1)
    }
}

test(0)

answered Dec 5, 2016 at 20:38

idbehold

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Comments

Jordan Running · Accepted Answer · 2016-12-05 20:49:56Z

2

It's not clear to me why you're using recursion and a for loop for basically the same task. Your desired result is easy to produce using recursion alone:

function test(x, y) {
  if (x > 3) {
    return;
  }
  
  if (y === undefined) {
    y = 0;
  } else if (y > 9) {
    return test(x + 1);
  }
  
  console.log('%d - %d', x, y);
  test(x, y + 1);
}

test(0);

answered Dec 5, 2016 at 20:49

Jordan Running

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