PHP function to remove specified variables in a URL

Question

I have created this function to remove specific variables from a string

if(!function_exists("remove_variable")) {
    function remove_variable($remove = array(), $url) {
        if($url == '') {
            $url = $_SERVER["REQUEST_URI"];
        }

        foreach($remove as $r) {
            echo $r.'<br>';
            $url = preg_replace('/([?&])'.$r.'=[^&]+(&|$)/','$1', $url);
            echo $url.'<br><br>';
        }

        return $url;
    }
}

I am testing with:

<?php echo remove_variable(array("productsearch_name", "productsearch_type", "productsearch_supplier"), $_SERVER["REQUEST_URI"].uri_glue()); ?>

Which is returning:

productsearch_name
/companies/customers/pricelist?productsearch_name=&productsearch_type=Broadband%20&productsearch_supplier=&

productsearch_type
/companies/customers/pricelist?productsearch_name=&productsearch_supplier=&

productsearch_supplier
/companies/customers/pricelist?productsearch_name=&productsearch_supplier=&

/companies/customers/pricelist?productsearch_name=&productsearch_supplier=&

So it is not removing the variables as expected

And then array_diff_key() with the array you want to remove. — AbraCadaver
– AbraCadaver, Commented Dec 5, 2016 at 21:01

Rahul · Accepted Answer · 2017-04-24 10:07:56Z

1

You can achieve this way,

$str = "http://google.com/companies/customers/pricelist?productsearch_name=asd&productsearch_type=Broadband%20&productsearch_supplier=test";
parse_str(parse_url($str)['query'],$output);
print_r($output);

parse_str — Parses the string into variables.
parse_url — Parse a URL and return its components

I hope this will solve your problem.

answered Apr 24, 2017 at 10:07

Rahul

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