Lambda function in classes

Question

class Test:
   def generate_attachment(self, type, owner_id, media_id):
       return type + str(owner_id) + '_' + str(media_id)

How to represent this function like a lambda function? Do I need mark 'self' in the lambda variables?

What exactly are you trying to do?

Patrick Haugh
– Patrick Haugh

2016-12-05 21:06:10 +00:00
Commented Dec 5, 2016 at 21:06 — Patrick Haugh
– Patrick Haugh, Commented Dec 5, 2016 at 21:06

Rok Povsic · Accepted Answer · 2016-12-05 21:16:30Z

2

No, you can just do this:

my_lambda = lambda type, owner_id, media_id: type + str(owner_id) + '_' + str(media_id)

Using a parameter called type is a bad idea though since a function by that name already exists in Python and you overwrite it.

edited Dec 5, 2016 at 21:16

answered Dec 5, 2016 at 21:07

Rok Povsic

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3 Comments

mipadi Over a year ago

You won't be able to call it like a method, though. Or rather, the type parameter will be the instance the "method" was called on. So you'd call it like t = Test(); t.my_lambda(owner_id, media_id), and type would be the t object. Probably not what the OP wants.

Rok Povsic Over a year ago

As provided, the function doesn't use self.

mipadi Over a year ago

self (the object of a method call) is always passed to a method as the first parameter.

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