How Do I Combine Two Numbers in a Variable Without Adding Them? - Python

Question

I have a basic Python encryption program. The program is pretty much done, but I keep getting errors because of the way Python is building my variable.

Here is an example of what I am trying to do:

A = 4
B = 2
C = 3

for i in range (3):
     A=A, ((B*2) + C)

A = (((4, 7), 7), 7)

I want A to output 4, 7, 7, 7 and as it loops, it adds numbers onto the end instead of adding them together. The issue here is that for whatever reason, I can't target specific values, for example, if I did

print (A[2])

The output would be an error

Traceback (most recent call last):
  File "C:/Users/name/Desktop/Python/Test.py", line 8, in <module>
    print (A[2])
IndexError: tuple index out of range

Ignoring the above code, what is the best way I could do this? Thanks!

So in essence, you want A to be a list and append to it in each loop? — dhke
– dhke, Commented Dec 7, 2016 at 17:19

SparkAndShine · Accepted Answer · 2016-12-07 17:19:10Z

1

Did you mean this,

A = 4
B = 2
C = 3

l = [A]
for i in range (3):
    l.extend([B*2 + C])

print(l)
# [4, 7, 7, 7]

answered Dec 7, 2016 at 17:19

SparkAndShine

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2 Comments

Spookichicken Over a year ago

Yes. Thank you, some how I forgot I could use and append a list. Will mark is as answered when I can. :)

SparkAndShine Over a year ago

@Spookichicken, you can do that any time.

Rodolfo · Accepted Answer · 2016-12-07 17:22:43Z

0

If you want to keep using a tuple you can do it like this:

A = 4
B = 2
C = 3

A = (A,) # Convert A to tuple
for i in range(3):
     A += ((B*2) + C,)

print(A)
# (4, 7, 7, 7)

Note: tuples are immutable, which means you are creating a new tuple in each iteration, this can be an expensive operation if the loop is very big.

answered Dec 7, 2016 at 17:22

Rodolfo

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