Member function pointer array

Question

In A.h:

class A 
{
    typedef void (A::*fp)();
    void test1();
    void test2();
    A(int a);
}

In A.cpp I have:

A::A(int a)
{
    fp fpointers[] = {&A::test1,&A::test2};

    fpointers[a]();
}
void A::test1()
{
//do something
}
void A::test2()
{
//do something
}

This is a reduced and simplified version of what I have. But the problem is still valid. From my humble experience 'fpointers' is how you define and declare an array of function pointers. I am having problem with line fpointers[a]();I am getting this error:

expression preceding parentheses of apparent call must have (pointer-to-) function type

What am I doing wrong?

Off topic: Take a look at std::function. Bit more runtime overhead, but cleans up some of the messiness of method pointer syntax. Especially interesting with lambda expressions and std::bind. — user4581301
– user4581301, Commented Dec 7, 2016 at 18:44

Jarod42 · Accepted Answer · 2016-12-07 18:38:50Z

4

Syntax would be

(this->*fpointers[a])();

as you need instance.

answered Dec 7, 2016 at 18:38

Jarod42

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