jQuery .append() function error

Question

I am facing an error (Oops, try again. Make sure to use .append() to add your item to your). when I tried with $('<div class="item">' + toAdd + '</div>')..append('.list'); Its working fine but I couldn`t find a solution or reason why .append() function talking two periods instead of one. It would be a big help for me if anyone can give me a solution.

$(document).ready(function(){
   $('#button').click(function(){
       var toAdd = $('input[name=checkListItem]').val();
       $('<div class="item">' + toAdd + '</div>').append('.list')

   });
 
});

h2 {
    font-family:arial;
}

form {
    display: inline-block;
}

#button{
    display: inline-block;
    height:20px;
	width:70px;
	background-color:#cc0000;
	font-family:arial;
	font-weight:bold;
	color:#ffffff;
	border-radius: 5px;
	text-align:center;
	margin-top:2px;
}

.list {
	font-family:garamond;
	color:#cc0000;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!DOCTYPE html>
<html>
    <head>
    	<title>To Do</title>
        <link rel="stylesheet" type="text/css" href="stylesheet.css"/>
        <script type="text/javascript" src="script.js"></script>
	</head>
	<body>
		<h2>To Do</h2>
		<form name="checkListForm">
			<input type="text" name="checkListItem"/>
		</form>
		<div id="button">Add!</div>
		<br/>
		<div class="list"></div>
	</body>
</html>

No i mean`t append(). For example So I append my order with another burger: myOrder.append(another burger). Or, I might say: I'd like to take a burger and append it to my order: burger.appendTo(myOrder). take this new thing and appendTo an already existing thing vs take already existing thing and append this new thing — Md Mehadi Hasan Mozumder
– Md Mehadi Hasan Mozumder, Commented Dec 10, 2016 at 5:48

Smit · Accepted Answer · 2016-12-10 05:36:14Z

$(document).ready(function(){
   $('#button').click(function(){

       var toAdd = $('input[name=checkListItem]').val();
   
       $('div.list').append('<div class="item">' + toAdd + '</div>')

   });
 
});

h2 {
    font-family:arial;
}

form {
    display: inline-block;
}

#button{
    display: inline-block;
    height:20px;
	width:70px;
	background-color:#cc0000;
	font-family:arial;
	font-weight:bold;
	color:#ffffff;
	border-radius: 5px;
	text-align:center;
	margin-top:2px;
}

.list {
	font-family:garamond;
	color:#cc0000;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!DOCTYPE html>
<html>
    <head>
    	<title>To Do</title>
        <link rel="stylesheet" type="text/css" href="stylesheet.css"/>
        <script type="text/javascript" src="script.js"></script>
	</head>
	<body>
		<h2>To Do</h2>
		<form name="checkListForm">
			<input type="text" name="checkListItem"/>
		</form>
		<div id="button">Add!</div>
		<br/>
		<div class="list"></div>
	</body>
</html>

Randy Stiven Valentín · Accepted Answer · 2016-12-10 05:41:50Z

Like this?

$(document).ready(function(){
   $('#button').click(function(){
       var toAdd = $('input[name=checkListItem]').val();
       $('<div />',{html:toAdd,class:"item"}).appendTo('.list')

   });
 
});

h2 {
    font-family:arial;
}

form {
    display: inline-block;
}

#button{
    display: inline-block;
    height:20px;
	width:70px;
	background-color:#cc0000;
	font-family:arial;
	font-weight:bold;
	color:#ffffff;
	border-radius: 5px;
	text-align:center;
	margin-top:2px;
}

.list {
	font-family:garamond;
	color:#cc0000;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!DOCTYPE html>
<html>
    <head>
    	<title>To Do</title>
        <link rel="stylesheet" type="text/css" href="stylesheet.css"/>
        <script type="text/javascript" src="script.js"></script>
	</head>
	<body>
		<h2>To Do</h2>
		<form name="checkListForm">
			<input type="text" name="checkListItem"/>
		</form>
		<div id="button">Add!</div>
		<br/>
		<div class="list"></div>
	</body>
</html>

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