class Method {
public static void main(String[] args) {
int a =1, b=2;
method1(a,b);
method2();
}
public static int method1(int a, int b) {
int c = (a + b);
return c;
}
public static void method2() {
int z=11;
if (z >= method1(a,b)) {System.out.println("Method 2 works");}
}
}
-getting enter image description hereerror in if statement
You have not declared variables a and b inside method2, which is causing the error you are seeing.
If you want to use local variables wihthin methods you can try the following:
public static void method2() {
int a = 1;
int b = 2;
int z=11;
if (z >= method1(a,b)) {System.out.println("Method 2 works");
}
If method 2 needs resulting input from another methods then you can do in several ways, is more just like a design style
You can do:
public static void method2(int x) {
int z=11;
if (z >= x) {System.out.println("Method 2 works");}
}
And call it by doing
method2(method1(a,b));
a,b variables are not global.So those variables are local to those methods in which they are defined.
In method 2 you have not defined a,b variables and tried to access them.
For this pass the variables to method2 also as done for method1 or store the method1 result in a variable and pass that variable to method2 and then compare.
Thank you all for your help. Finaly I got it. I am trying to learn different ways of applying methods. Now it works fine.
class Method {
public static void main(String[] args) {
int a = 1, b = 2, e = 3;
System.out.println(method1(a, b));
System.out.println(method2(a, b, e));
method3();
}
public static int method1(int a, int b) {
int c = (a + b);
System.out.print("Method 1 burada işləyir ");
return c;
}
public static int method2(int a, int b, int e) {
int q = (a + b + e);
System.out.print("Method 2 işləyir və nəticə ");
return q;
}
public static void method3() {
int z = 11;
int a = 4;
int b = 6;
if (z >= method1(a, b)) {
System.out.println("Method 3 işləyir");
}
}
}
package com.ZJAVAKITABI;
class Method {
public static void main(String[] args) {
int a = 1, b = 2, e = 3;
System.out.println(method1(a, b, e));
System.out.println(method2());
method3();
method4();
System.out.println(method5(a, b));
}
public static int method1(int a, int b, int e) {
int q = (a + b + e);
System.out.print("3 parametrli Method 1 işləyir və nəticə ");
return q;
}
public static int method1(int a, int b) {
int mf = (a + b);
System.out.print("2 parametrli Method1 işləyir. Nəticə: ");
return mf;
}
public static int method2() {
int a = 4, b = 6;
int z = a + b;
System.out.print("Method 2 işləyir və nəticə ");
return z;
}
public static void method3() {
System.out.println("Method 3 işləyir, Void nəticə vermir");
}
public static void method4() {
int v = 5, m = 5;
int n = v + m;
System.out.println("Method 4 işləyir, hesablama nəticəsi " + n);
}
public static int method5(int a, int b) {
int u = 9;
System.out.print("Method 5 və daxilindəki ");
int s = method1(a, b) + u + 2;
return s;
}
}
aandbare method arguments, not result. They are undefined inmethod2. What are you trying to sum inmethod2? Whatzshould be greater than?