javascript async/await in a generic loop

Question

Is this the correct implementation?

        let times= async (n,f)=>{while(n-->0) await f();} 

        times(5,()=>
               myfunc([1,2,3],err => err)
              )

myfunc is itself an async function awaiting for various other functions:

async myfunc(params,cb){

   await a( err => err )
   await b( err => err )
   await c( err => err )

}`

async/await doesn't make code synchronous. It just enables a more convenient way of writing asynchronous code. And yeah, that looks like it should work (why don't you just try it?), although I'd rather write async () => await myfunc([1,2,3],err => err). — Felix Kling
– Felix Kling, Commented Dec 14, 2016 at 0:19
What do you mean by "make synchronous"? Or is it a typo and you meant asynchronous? — Bergi
– Bergi, Commented Dec 14, 2016 at 1:16
That err => err callback you are passing but not using anywhere does not look like correct usage of async functions. — Bergi
– Bergi, Commented Dec 14, 2016 at 1:17

Bergi · Accepted Answer · 2016-12-14 01:21:16Z

10

Is this the correct implementation?

Yes. await works in loops like you'd expect it to, if that was your actual question.
I would however recommend to write

async function times(n, f) {
    while (n-- > 0)
        await f();
}

answered Dec 14, 2016 at 1:21

Bergi

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