Check if two char from array are present(together) in a string

Question

I have an array of characters -

$operators = array('%', '*', '+', '-', '@');

and a string for eg-

$text = '%@';

How can I find if the string contains two values from the array in concatenation -

Like $text = %test% - valid, but $text = %+test should fail ($concat = TRUE).

This is what I've tried -

$concat = FALSE;
foreach ($operators as $op) {
  $opPosition[$op] = strpos($text, $op);
  // Here I need to check if any two values of
  // $opPosition are neighbours, set the $concat variable to TRUE.
}

How do I make a check for $opPosition or is this the only way what I'm trying ?

Dig a little into regular expressions. I think that this would be helpful: preg_match_all() — Raphioly-San
– Raphioly-San, Commented Dec 14, 2016 at 6:39
@bansi As I have a whole array to check from, thought the regex would a long string to configure — jitendrapurohit
– jitendrapurohit, Commented Dec 14, 2016 at 6:49

bansi · Accepted Answer · 2016-12-14 09:41:10Z

1

You can use preg_match like below.

// $concat will be 1 for any match
$concat = preg_match("/[%\*\+\-@]{2,}/", $text);

You can find the explanation for the regular expression here

Note: $concat will be 0 even if some error occurs. You may need to use == operator.

Edit: if your operators are in and array, or need flexibility to add, change or remove operators without disturbing the regular expression you can use the following code.

$text = "test%+";
$operators = array('%', '*', '+', '-', '@');
// create regular expression by imploding the array to string and using
// preg_quote to Quote regular expression characters
$expression = preg_quote(implode('', $operators), '/');
$concat = preg_match("/[$expression]{2,}/", $text);

Reference for preg_quote

Demo here

edited Dec 14, 2016 at 9:41

answered Dec 14, 2016 at 9:24

bansi

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Comments

Rahul Khandelwal Systematix · Accepted Answer · 2016-12-14 07:24:04Z

0

Try to Use this code section to get your desired output -

$operators = array('%', '*', '+', '-', '@');
$text = '%test%';
$end = substr($text,-1);
$start = substr($text, 0,1);
if(($start == $end) && in_array($start, $operators) == 1){
  echo "valid";
}else{
  echo "Not Valid";
}

answered Dec 14, 2016 at 7:24

Rahul Khandelwal Systematix

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