c# Byte to Image ArgumentOutOfRangeException

Question

I have a little problem to convert byte array to Bitmap. Here is my exception:

An unhandled exception of type 'System.ArgumentOutOfRangeException' occurred in mscorlib.dll

My code:

public static System.Drawing.Bitmap ByteToImage(byte[] data)
{
    System.Drawing.Bitmap bmp;
    using (var ms = new MemoryStream(data))
    {
        bmp = new System.Drawing.Bitmap(ms);
    }
    return bmp;
}

Bitmap b = ByteToImage(editor1.system.Tiles[0].ImageData);
Form f = new Form();
f.BackgroundImage = b;
f.Show();

I need to load a serialized byte array on the list and convert to an image at runtime.

If I save the bitmap

b.Save(@"C:\test.png");

It works if I try to load bitmap at runtime I get this error.

@Happypig375 editor1 is a my userControl, system is a library for serialize all element, contains list, struct and more. — Joe Martiniello
– Joe Martiniello, Commented Dec 18, 2016 at 9:02
It is failing because the array data does not contain valid image data. The usually occurs because you don't have all the data or you used a stream method that didn't use Encoding.UTF8. The default encoding (even though Microsoft is UTF8) is actually jASCII which will alter binary data. I usually start by verifying the number of bytes in the data matches the number of bytes of where the source of the image came from. The find where the byte count changed. — jdweng
– jdweng, Commented Dec 18, 2016 at 11:21

Prasad KM · Accepted Answer · 2018-01-17 08:30:59Z

1

Use the bellow code, it will resolve your issue.

    public static Image FormatImage(Image img, int outputWidth, int outputHeight)
    {

        Bitmap outputImage =null;
        Graphics graphics = null;
        try
        {
            outputImage = new Bitmap(outputWidth, outputHeight, System.Drawing.Imaging.PixelFormat.Format16bppRgb555);
            graphics = Graphics.FromImage(outputImage);
            graphics.DrawImage(img, new Rectangle(0, 0, outputWidth, outputHeight),
            new Rectangle(0, 0, img.Width, img.Height), GraphicsUnit.Pixel);

            return outputImage;
        }
        catch (Exception ex)
        {                
           return img;
        }

}

answered Jan 17, 2018 at 8:30

Prasad KM

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