JSON parsing of multidimensional JSON Object in PHP

Question

I have the following JSON on a page

{   
"users": [
        {
            "name": "John",
            "age": "30",
        },
        {
            "name": "Dave",
            "age": "20",
        },
         ...
      ]
    }

I'm decoding it using $json = json_decode($data);. If I want a loop that print every name and age for each user how can I do that?

I'm tring to do something like the following code but it's not working

foreach($json->users->name as $key => $result){
        $name = $result;
        $age = $result->age;

        echo $name;
        echo $age;
        echo "<br>";
}

What am I doing wrong? How could I achieve that?

print_r($json->users) What do you see?

u_mulder
– u_mulder

2016-12-19 14:18:34 +00:00
Commented Dec 19, 2016 at 14:18 — u_mulder
– u_mulder, Commented Dec 19, 2016 at 14:18
Trying to get property of non-object in <file> on line 44

L. K.
– L. K.

2016-12-19 14:19:59 +00:00
Commented Dec 19, 2016 at 14:19 — L. K.
– L. K., Commented Dec 19, 2016 at 14:19

Saumya Rastogi · Accepted Answer · 2016-12-19 14:20:13Z

1

You can do it like this:

$string = "{\"users\": [{\"name\": \"BA8842_530\",\"age\": \"0.0\"},{\"name\": \"BA8842_540\",\"age\": \"20\"}]}";
$json = json_decode($string, true);
foreach ($json['users'] as $key => $value) {
    echo "Name: " . $value['name'] . "<br>";
    echo "Age: " . $value['age'] . "<br>";
}

The output would be:

// Output
Name: BA8842_530
Age: 0.0
Name: BA8842_540
Age: 20
...

Hope this helps!

answered Dec 19, 2016 at 14:20

Saumya Rastogi

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4 Comments

L. K. Over a year ago

Worked! Thanks a lot, was going crazy hahah

Saumya Rastogi Over a year ago

@L.K. - If you find this answer correct and helpful then accept & upvote this answer as it motivates me to give answers to other questions like this and helps others to quickly find the correct answer!

L. K. Over a year ago

Was waiting 5 minutes to do so ;)

Saumya Rastogi Over a year ago

Glad to know, that it helped you. Thanks! :D

Paladin · Accepted Answer · 2016-12-19 14:20:28Z

1

foreach($json->users as $row){
        echo $row->name;
        echo $row->age;
        echo "<br>";
}

answered Dec 19, 2016 at 14:20

Paladin

1,63715 silver badges29 bronze badges

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