String st="1a2b3j4";
char ar[]=st.toCharArray();
int sum=ar[0]+ar[2];//how to add the numbers
when i try to add its taking ASCII values
how to convert chat'1' to integer
4 Answers
You just must convert the character to String and then use something like this:
int sum = Integer.parseInt(stringNum1) + Integer.parseInt(stringNum2);
1 Comment
Wasi Ahmad
this will raise
NumberFormatException if stringNum1 or stringNum2 is an alphabet. you need to handle that case.If you want to convert character ASCII numeric value, just cast your char as an int
like char character = arr[0];
int asciiValue = (int) character;
1 Comment
Andreas
That will get the ASCII value, not the numeric "digit" value.
Are you looking for this?
String st = "1a2b3j4";
char ar[] = st.toCharArray();
int sum = 0;
for (int i = 0; i < ar.length; i++) {
sum += (ar[i] - '0');
}
System.out.println(sum); // prints 167 (1 + 49 + 2 + 50 + 3 + 58 + 4)
If you want to consider the ASCII value for the alphabets but the numeric digits itself, then you can try as following.
String st = "1a2b3j4";
char ar[] = st.toCharArray();
int sum = 0;
for (int i = 0; i < ar.length; i++) {
if (ar[i] >= '0' && ar[i] <= '9') {
sum += (ar[i] - '0');
} else {
sum += ar[i];
}
}
System.out.println(sum); // prints 311 (1 + 97 + 2 + 98 + 3 + 106 + 4)
Note that, ASCII values for 1,a,2,b,3,j,4 are 49,97,50,98,51,106,52.
Comments
just add (int) at the beginning of each array elements. ie int sum=(int)ar[0]+(int)ar[2]; hope this helps;
1 Comment
Farbod Ahmadian
Please try to markdown your code and provide more information for further detail.
Integer.parseInt(value)? I'm rather confused what the actual question is, sorry.'0'.