ValueError when performing integration in Numpy

Question

I am receiving a ValueError which I cannot decifer. I am tryig to perform a simple integration task, using the integrate.quad on a lambda function. Here is the code:

import numpy as np
p = np.arange(0,1,1/1000)
x = 0
y = 1
z = 0.9
pdfl = lambda p: 2*(p-x)/((y-x)*(z-x)) if p<z else 2*(y-p)/((y-x)*(y-z))
h = lambda pp: integrate.quad(lambda p: p*pdfl(p), 0, pp)

In this code, pdfl is the probability density function of a (skewed) triangular distribution. Now, this function works for particular numbers, that is, h(0.5) gives us an answer as desired. However, I would like to have h evaluated at each of the elements in p. But when I do h(p), I get the exception:

  File "d:\Anaconda3\lib\site-packages\scipy\integrate\quadpack.py", line 315, in quad
    points)

  File "d:\Anaconda3\lib\site-packages\scipy\integrate\quadpack.py", line 364, in _quad
    if (b != Inf and a != -Inf):

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

Any advice on how to overcome this error? Thank you.

hpaulj · Accepted Answer · 2016-12-23 18:57:30Z

2

This error, as you can see from the side bar questions, is the result of using an array in a context that expects a scalar True/False.

My guess is the quad is testing the bounds, pp against inf. It works fine when you give it one bounds, e.g. 0.5, but produces this error when you give it an array of bounds, p. quad is designed to work with one set of bounds at a time, not an array.

I think you need to do something like

res = [h(pp) for pp in p]

that is, iterate, performing the integration for one bound value at a time.

answered Dec 23, 2016 at 18:57

hpaulj

233k14 gold badges260 silver badges392 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

ValueError when performing integration in Numpy

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related