Pass the parameter only for non-empty variable in AJAX data

Question

Here I want to do which are the variable not empty, I want to pass that variable one in data,in this case area is empty so I want pass the parameter for city and listing type, but I don't know how to do?

var city = "Karnadaka";
var area = "";
var listing type = "RENT";

$.ajax({
    type: 'GET',
    url: "http://www.domain.com/api/get/searchProperties",
    data: {
        area: area,
        city: city,
        listingType: listing_type
    },
    success: function(data) {
        console.log(data);
    }
});

Create an object, check if value is not empty then add to object var data = {}; if (area) { data.area = area; } if (city) { data.city = city; } ... And use this object to pass data to ajax request data: data, — Tushar
– Tushar, Commented Dec 26, 2016 at 6:41
From where i have to check this empty or not, can pls update your answer — Sagunthala K
– Sagunthala K, Commented Dec 26, 2016 at 6:51

Liang · Accepted Answer · 2016-12-26 07:01:28Z

1

you can use delete to remove the propery pair(s) in an Object

var city = "Karnadaka";
var area = "";
var listing_type = "RENT";

var data={
        area: area,
        city: city,
        listingType: listing_type
    }

for (k in data){
    if(data[k]=="") delete data[k];
}

$.ajax({
    type: 'GET',
    url: "http://www.domain.com/api/get/searchProperties",
    data: data,
    success: function(data) {
        console.log(data);
    }
});

answered Dec 26, 2016 at 7:01

Liang

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Comments

Yajnesh Rai · Accepted Answer · 2016-12-26 07:04:41Z

0

Try this:

var city = "Karnadaka";
var area = "";
var listing_type = "RENT";

var data = {};

if(city != '')
    data['city'] = city;

if(area != '')
    data['area'] = area;

if(listing_type != '')
    data['listing_type'] = listing_type;

$.ajax({
    type: 'GET',
    url: "http://www.domain.com/api/get/searchProperties",
    data: data,
    success: function(response) {
        console.log(response);
    }
});

answered Dec 26, 2016 at 7:04

Yajnesh Rai

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2 Comments

Sagunthala K Over a year ago

Yajnesh Rai @ your code is woking but while going dynamic it is not working that means area is ,i tried console.log(area) it is coming blank so that time it is not working what i have to do

Yajnesh Rai Over a year ago

Thanks @SagunthalaK. If there is any further requirement on dynamic code, please post that as well

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