PHP preg_replace in foreach loop

Question

I am trying to use preg_replace in a foreach loop.

I need to replace all keywords wrapped between '%' and use the back reference.

For example, in my text I have few keywords like %author% %title% I need to replace the keywords so they look like $items->author and $items->title

I have tried with the following code but it just displays $items->author as a text and not retrieving the info from the array.

      foreach ($xml->book as $items) {
           echo preg_replace('/\%(.*?)\%/e', '$items->${1}', $content);
      }

Any idea for this ?

You can try with echo preg_replace('/\%(.*?)\%/e', $items->${1}, $content); — Hackerman
– Hackerman, Commented Dec 27, 2016 at 16:08

Scott Anderson · Accepted Answer · 2021-05-28 18:49:11Z

1

You will have to use preg_replace_callback for this. You cannot just put code as the second parameter in the preg_replace function.

Like this:

<?php

    foreach ($xml->book as $items) {
        echo preg_replace_callback('/\%(.*?)\%/e', function ($matches) use ($items) {
            return $items->{$matches[1]};
        }, $content);
    }

Also, it would be best to check if a match was found and if the $items array contains a key with this name.

edited May 28, 2021 at 18:49

Scott Anderson

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answered Dec 27, 2016 at 16:09

Jerodev

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1 Comment

Jerodev Over a year ago

Glad I could help. Please mark this as the solution to your question if this solved your problem. :)

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