Remove certain string parts in PHP with regex

Question

I am trying to remove certain parts of my string using preg_match. I do not know if this is the best scenario.

I have the following string:

Uploaded Today 13:11, Size 117.09 MiB, ULed by demonoidt

I want to get only the 117.09 part of the string. I am using preg_match like this:

$res = preg_replace("/[^0-9]/", "", $string);

But this will return all the numbers found in the string, so I would have something like:

131111709

Any help would be greatly appreciated. Thank you and happy holidays.

The quickest way to end up with 117.09 would be $var = "117.09" This is obviously not what you meant, but i can think of any number of substring operations that would only work for this case. Could you clarify why you want that part? — S van Balen
– S van Balen, Commented Dec 28, 2016 at 12:56
It will never be the same, the information is stored in an array. that whole uploaded... and so on so it will not be just 117.09, that can change easily so that is why I went for the preg_replace at the first time, to find just the numbers in that string. — Cristian Badea
– Cristian Badea, Commented Dec 28, 2016 at 13:27

Wiktor Stribiżew · Accepted Answer · 2016-12-28 14:51:36Z

6

You should be using a matching approach rather than the replacing one.

Use

/([\d.]+)\s*MiB/

Or, if the Size word is always before the number, then use

/Size\s*([\d.]+)/

and grab Group 1 value. See the regex demo (or this demo).

Pattern details:

([\d.]+) - Group 1 capturing 1 or more digits or .
\s* - 0+ whitespaces
MiB - a sequence of literal chars.

NOTE that you may make the number matching part more precise by replacing [\d.]+ with \d*\.?\d+.

PHP demo:

$re = '/([\d.]+)\s*MiB/';
$str = 'Uploaded Today 13:11, Size 117.09 MiB, ULed by demonoidt';
if (preg_match($re, $str, $match)) {
  echo $match[1]; // => 117.09
}

edited Dec 28, 2016 at 14:51

answered Dec 28, 2016 at 12:53

Wiktor Stribiżew

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Comments

Sougata Bose · Accepted Answer · 2016-12-28 13:00:13Z

2

You can try this also -

$s = 'Uploaded Today 13:11, Size 117.09 MiB, ULed by demonoidt';

preg_match('/\d*\.\d*/', $s, $match);

var_dump($match[0]);

Output

string(6) "117.09"

\d* matches a digit (equal to [0-9])

Test

answered Dec 28, 2016 at 13:00

Sougata Bose

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Comments

d.coder · Accepted Answer · 2016-12-28 12:58:40Z

1

You can get it by following regex:

$re = '/(?<=Size )(\d.)+/';
$str = 'Uploaded Today 13:11, Size 117.09 MiB, ULed by demonoidt';
if (preg_match($re, $str, $match)) {
  echo $match[0]; // => 117.09
}

answered Dec 28, 2016 at 12:58

d.coder

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Comments

lazyCoder · Accepted Answer · 2016-12-28 13:22:13Z

-1

@Cristian Badea if you want to extract particular part of string like 117.09 from your string so you can also get this by the php string function

try the below strpos, substr function to get your 117.09 string from the whole string

<?php
    $a = "Uploaded Today 13:11, Size 117.09 MiB, ULed by demonoidt";
    $extract = "117.09";
    if(strpos($a, $extract)){
        $b = substr($a, strpos($a, $extract), strlen($extract));
        echo $b;
    }
?>

In $b you will get your 117.09 part of string (y)

answered Dec 28, 2016 at 13:22

lazyCoder

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2 Comments

Cristian Badea Over a year ago

I need to be dynamic so I will never have 117.09 ... and the entire string is generated automatically, so I will have to get the size part.

Wiktor Stribiżew Over a year ago

How come this is an accepted answer? The 117.09 is a value to be extracted, it is not known beforehand. Its length is not known either, it can be 30, or 5.

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