how to create class reference using String

Question

so here's the problem that I'm facing. Take a look

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    if indexPath.row == 0 {
        let cell = tableView.dequeueReusableCell(withIdentifier: "ExpenseTableViewCell_Title") as! ExpenseTableViewCell_Title
        return cell
    } else {
        let cell = tableView.dequeueReusableCell(withIdentifier: "ExpenseTableViewCell_SaveCanel") as! ExpenseTableViewCell_SaveCanel
        return cell
    }
}

what i want to do is, use cell identifier string as cell type.(i.e. ExpenseTableViewCell_Title, ExpenseTableViewCell_SaveCanel).

I do have cell identifier array.

var TableCell:[ExpenseCellType] = [.ExpenseTableViewCell_Title, .ExpenseTableViewCell_SaveCanel]

Right now I only have two types of cell. But this number will go high. And I don't want to use if/else condition or switch case.

Thank in advance.

Swift is strict with type checking. So you can't avoid this. — Lumialxk
– Lumialxk, Commented Dec 30, 2016 at 9:26

Tj3n · Accepted Answer · 2016-12-30 09:58:21Z

3

Can make it shorter with extension:

extension UITableView {
    func dequeueReusable<T>(type: T.Type, index: IndexPath) -> T {
        return self.dequeueReusableCell(withIdentifier: String(describing: T.self), for: index) as! T
    }
}

Use it like this, will return ExpenseTableViewCell_Title type cell:

let cell = tableView.dequeueReusable(type: ExpenseTableViewCell_Title.self, index: indexPath)

Just store your class in the array like [ExpenseTableViewCell_Title.self, ExpenseTableViewCell_SaveCanel.self] and pass it to this function

edited Dec 30, 2016 at 9:58

answered Dec 30, 2016 at 9:52

Tj3n

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1 Comment

rv7284 Over a year ago

Thanks, I'll try this.

PlusInfosys · Accepted Answer · 2016-12-30 09:45:32Z

2

You can use function NSClassfromString but you will need namespace for getting class from String.

I have created example here to use it. Example:

func getClassFromString(_ className: String) -> AnyClass! {


    let namespace = Bundle.main.infoDictionary!["CFBundleExecutable"] as! String;
    let cls: AnyClass = NSClassFromString("\(namespace).\(className)")!;

    return cls;
}


    class customcell: UITableViewCell {

        }   

    let requiredclass = getClassFromString("customcell") as! UITableViewCell.Type
    let cellInstance = requiredclass.init()

edited Dec 30, 2016 at 9:45

answered Dec 30, 2016 at 9:23

PlusInfosys

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1 Comment

rv7284 Over a year ago

thanks for your answer, but I could find any function named "stringClassFromString". although I did tried "NSClassFromString". That didn't worked either.

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