PHP - object array into json

Question

array of $setting['accountType'] :

$setting['accountType']['all'] = 'ALL';
$setting['accountType']['A1'] = 'VIP1';
$setting['accountType']['A2'] = 'VIP2';

PHP code to generate the object:

$object = new stdClass();
    $myArray = array();
    foreach ($setting['accountType'] as $key => $val)
    {                       
        $object->id = $key;
        $object->desc = $val;
        $myArray[] = $object;       
    }
    $accountType = $myArray;

PHP code to format object into json:

json_encode(['accountType'=> [(object)$accountType]));

However, i get the output as below :

"accountType": [{
    "0": {
        "id": "A2",
        "desc": "VIP"
    },
    "1": {
        "id": "A2",
        "desc": "VIP"
    },
    "2": {
        "id": "A2",
        "desc": "VIP"
    }
}]

Problem 1: why $accountType only keep the last object when I loop through?

Problem 2: without the array key of $accountType [solved by using array_values($accountType)]

This is something that I am trying to achieve:

"accountType": [{
        "id": "all",
        "desc": "All "
    }, {
        "id": "A1",
        "desc": "Normal"
    }, {
        "id": "A2",
        "desc": "VIP"
    }]

How to get the output as above?

Why do you want it to be an object of stdClass?

Praveen Kumar Purushothaman
– Praveen Kumar Purushothaman

2017-01-04 11:04:23 +00:00
Commented Jan 4, 2017 at 11:04 — Praveen Kumar Purushothaman
– Praveen Kumar Purushothaman, Commented Jan 4, 2017 at 11:04
Can you print $setting['accountType'] ?

Rahul
– Rahul

2017-01-04 11:09:04 +00:00
Commented Jan 4, 2017 at 11:09 — Rahul
– Rahul, Commented Jan 4, 2017 at 11:09
json_encode(['accountType'=> $accountType]);

bansi
– bansi

2017-01-04 11:20:51 +00:00
Commented Jan 4, 2017 at 11:20 — bansi
– bansi, Commented Jan 4, 2017 at 11:20

bansi · Accepted Answer · 2017-01-04 11:53:03Z

1

You should use

json_encode(['accountType'=> $accountType]);

instead of

json_encode(['accountType'=> [(object)$accountType]]);

In your code you are putting $accountType inside another array that is why you are getting that result

Here is a Demo and Explanation

Edit: The entire code

$setting['accountType']['all'] = 'ALL';
$setting['accountType']['A1'] = 'VIP1';
$setting['accountType']['A2'] = 'VIP2';

$myArray = array();
foreach ($setting['accountType'] as $key => $val)
{                       
    $object = new stdClass(); // Note: $object should be created inside the loop
    $object->id = $key;
    $object->desc = $val;
    $myArray[] = $object;       
}
$accountType = $myArray;
echo json_encode(['accountType'=> $accountType]);

And Here is the Revised Demo

edited Jan 4, 2017 at 11:53

answered Jan 4, 2017 at 11:22

bansi

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5 Comments

Louis Lee Over a year ago

why i get the repeating value when I loop through the $setting['accountType'], and assign to $dealStatus ?

bansi Over a year ago

you mean in the demo? there the date is just for sample and have repeated it 3 times to have more data. The loop you use to generate is fine just use json_encode(['accountType'=> $dealStatus]);.

Louis Lee Over a year ago

i have amended the demo , and you can see it only keep {"id":"A1","desc":"VIP1"} , and the first object {"id":"A2","desc":"VIP"} is missing from $accountType

bansi Over a year ago

I have edited and added a new demo with the data in the question.

Maveňツ Over a year ago

@bansi please review carefully

Rahul · Accepted Answer · 2017-01-04 11:10:50Z

1

Try this,

echo json_encode(array_values($your_array));

Let me know if its working

answered Jan 4, 2017 at 11:10

Rahul

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1 Comment

Louis Lee Over a year ago

@V for Vendetta ok, this is part of the answer I am looking for ... thx

Banana · Accepted Answer · 2017-01-04 11:13:18Z

0

This is exactly the same thing, no? The numerotation is displayed because you need it to access to the specific json object. You have an array and you can access to each element by its key.

answered Jan 4, 2017 at 11:13

Banana

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