Concatenate binary strings obtained from decimal to binary conversion

Question

I want to place the binary equivalent number for each element side - by side i.e, the final matrix Concatenated_A would be of size m by nbits*n where [m,n] = size(A);

A = [5, 5,  4,  10, 4;
    10, 10, 10, 10, 5;

    ];

I did an attempt but the result is wrong. I need help in correctly implementing the concatenation. Thank you

[m,n] = size(A);
numbits = 4;
for m = 1:M

Abin = dec2bin(A(m,:),numbits);
for j = 1:size(Abin,1)
Concatenated_A(m,:) = Abin(j,:);
end

end

For first row in A(1,:) = 5, 5, 4, 10, 4 ; its decimal conversion of each element would give a matrix as below.

0   1   0   1
0   1   0   1
0   1   0   0
1   0   1   0
0   1   0   0

Then, how can I do something like this :

Concatenated_A(1,:) = [0 1 0 1 0 1 0 1 0 1 0 0 1 0 1 0 0 1 0 0]

The above operation is repeated for every row in A.

Suever · Accepted Answer · 2017-01-06 19:15:05Z

1

You can transpose the result of dec2bin so that the binary representation goes down the columns and then reshape this into the desired shape so that each row is on it's own row. After reshaping, we take the transpose again so that the rows go across the rows again. Also we need to be sure to transpose A before we start so that we encode along the rows.

out = reshape(dec2bin(A.', numbits).', [], size(A, 1)).'
%   01010101010010100100
%   10101010101010100101

Or if you want a logical matrix instead you can compare your character array to the character '1'

out = reshape(dec2bin(A.', numbits).', [], size(A, 1)).' == '1'
%   0 1 0 1 0 1 0 1 0 1 0 0 1 0 1 0 0 1 0 0
%   1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1 0 1

edited Jan 6, 2017 at 19:15

answered Jan 6, 2017 at 18:51

Suever

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1 Comment

Suever Over a year ago

@SrishtiM Oops! I'd missed a transpose! Fixed now.

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