Curl, not getting page source code

Question

In this script curl is working fine. $output has the page but when I try to echo its source code it displays nothing. I think it has something to do with page headers. Any help!!

header('content-type:text/plain');
$ch = curl_init();
$url = "https://www.amazon.com/gp/css/shiptrack/view.html/ref=TE_SIMP_typ?ie=UTF8&addressID=olqnkqjstjp&latestArrivalDate=1483848000&orderID=103-0753412-5410653&shipmentDate=1483706902&orderingShipmentId=4160817392100&packageId=1";
curl_setopt($ch, CURLOPT_URL, $url); 
curl_setopt($ch, CURLOPT_HEADER, false);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_BINARYTRANSFER, true);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, FALSE);

curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_MAXREDIRS, 1);
$output = curl_exec($ch);
curl_close($ch);
echo $output;

when debugging, use var_dump , not echo. var_dump is guaranteed to give some output, what does var_dump say? (most likely, it says bool(false) , meaning that curl had an error, in which case, use curl_error($ch) to get more info) — hanshenrik
– hanshenrik, Commented Jan 10, 2017 at 14:21
seems you're running without error reporting, and you reference an undefined variable called $curl (because the variable you want is called $ch , $curl is undefined), the script crashes, but without error_reporting in php.ini , you just get a blank page and no error log - make sure php.ini contains error_reporting=E_ALL, and run the code again and the error should be obvious from the error log — hanshenrik
– hanshenrik, Commented Jan 10, 2017 at 14:26
@rajeev singh can pls accept my answer by clicking on that tick mark near votes...so it will be helpful to others too(When u accept it will turn into green tick) — NID
– NID, Commented Jan 16, 2017 at 12:15

NID · Accepted Answer · 2017-01-10 09:02:11Z

1

I have modified your code.. Try this.

Remove
header('content-type:text/plain');

and replace your code with mine.

$ch = curl_init();
$url = "https://www.amazon.com/gp/css/shiptrack/view.html/ref=TE_SIMP_typ?ie=UTF8&addressID=olqnkqjstjp&latestArrivalDate=1483848000&orderID=103-0753412-5410653&shipmentDate=1483706902&orderingShipmentId=4160817392100&packageId=1";
curl_setopt($ch, CURLOPT_URL, $url); 
curl_setopt($ch, CURLOPT_HEADER, false);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);

curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_MAXREDIRS, 1);
$output = curl_exec($ch);
curl_close($ch);
echo $output;

EDIT

Since you want ctrl+u

Here is the PHP code to fetch the html source code of any website specified. fopen function is used to open the website URL. stream_get_contents is used to read the opened URL. The fetched code is displayed inside a textarea.

$domain = 'https://www.amazon.com/gp/css/shiptrack/view.html/ref=TE_SIMP_typ?ie=UTF8&addressID=olqnkqjstjp&latestArrivalDate=1483848000&orderID=103-0753412-5410653&shipmentDate=1483706902&orderingShipmentId=4160817392100&packageId=1';
$handle = fopen($domain, 'r');
$content = stream_get_contents($handle);
/**
// alternative to stream_get_contents
$contents = '';
while (!feof($handle)) {
    $content .= fread($handle, 8192);
}
**/ 
fclose($handle);
/** 
 * print html content on textarea
 */
echo "<textarea rows='20' cols='80'>$content</textarea>";

output will be like this:

OR

Also if you want to manipulate the retrieved page somehow, you might want to try some php DOM parser. I find PHP Simple HTML DOM Parser very easy to use.

edited Jan 10, 2017 at 9:02

answered Jan 10, 2017 at 7:33

NID

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10 Comments

Rajeev Singh Over a year ago

$output has the page but I want to get its html, that is where I am facing problem.

NID Over a year ago

Rajeev singh i didn't get u.. can u elaborate?? i thought you had problem with ur curl

Rajeev Singh Over a year ago

I want the html of the page so I can scrap some content from it.

Rajeev Singh Over a year ago

@bilal. sorry I was not clear b4. my curl is workinf fine and the $output contains the page that I want but I want that page html so I acn scrap some content from it.

NID Over a year ago

what exactly are u trying to do?

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