How to get all attribute names from selected XML node in C#

Question

This is my XML file. I need to select one test element and get all attributes name from its result child nodes.

<?xml version="1.0" encoding="UTF-8"?>
<summary>
  <test>
    <id>test 1</id>   
    <result value="-45">330</result>
    <result value="0">300</result>
    <result value="45">340</result>
  </test>
  <test>
    <id>test 3</id>    
    <result value="-45">330</result>
    <result value="0">300</result>
    <result value="45">340</result>
  </test>
</summary>

I wrote below code. but repeat same values and I want to stop it.

XmlDocument xd = new XmlDocument();
xd.Load(_xmlFilePath);

XmlNodeList nodelist = xd.GetElementsByTagName("result");

foreach (XmlNode node in nodelist)
    {
        string attrVal = node.Attributes["value"].Value;
        Console.WriteLine(attrVal);
    }

Any suggestion is appreciated.

Thanks.

Can u show what is expected value of nodelist and output of attrVal — Mohit S
– Mohit S, Commented Jan 10, 2017 at 8:36

Fabio · Accepted Answer · 2017-01-10 08:44:40Z

2

You can use LINQ to Xml with XDocument class

var doc = XDocument.Load(_xmlFilePath);

var distinctResults = doc.Descendants("result")
                         .Select(element => element.Attribute("value").Value)
                         .Distinct();

foreach(var result in distinctResults)
{
    Console.WriteLine(result);
}

Or with using of HashSet<string>

var results = doc.Descendants("result")
                 .Select(element => element.Attribute("value").Value);

var distinctResults = new HashSet<string>(results); 

foreach(var result in distinctResults)
{
    Console.WriteLine(result);
}

edited Jan 10, 2017 at 8:44

answered Jan 10, 2017 at 8:37

Fabio

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2 Comments

WEAPI Over a year ago

'System.Xml.XmlDocument' does not contain a definition for 'Descendants' and no extension method 'Descendants' accepting a first argument of type 'System.Xml.XmlDocument' could be found

Fabio Over a year ago

Use XDocument class instead of XmlDocument

jdweng · Accepted Answer · 2017-01-10 10:25:49Z

0

Try following :

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication34
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {

            XDocument doc = XDocument.Load(FILENAME);

            string id = "test 1";

            var results = doc.Descendants("test").Where(x => (string)x.Element("id") == id).FirstOrDefault().Elements("result").Select(x => new
            {
                angle = (int)x.Attribute("value"),
                length = (int)x
            }).ToList();

        }


    }


}

answered Jan 10, 2017 at 10:25

jdweng

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