How to separate array of comma separated string into various arrays?

Question

What's the best way to convert this array of comma separated values

[ 'com--test,LFutx9mQbTTyRo4A9Re5ksjdnfsI4cKN4q2,on',
  'com--fxtrimester,SEzlksdfMpW3FxkSbzL7eo5MmqkPczCl2,on',
  'com--fxtrimester,LFutx9mQbTTyRoldksfns4A9Re5I4cKN4q2,on' ]

Into three arrays?

[ 'com--test',           [ LFutx9mQbTTyRo4A9Re5Ilsdf4cKN4q2', ['on',
  'com--fxtrimester',      SEzMpW3FxkSbzL7eo5MmlkdfqkPczCl2',  'on',
  'com--fxtrimester' ]     LFutksdfx9mQbTTyRo4A9Re5I4cKN4q2 ]  'on']

I was trying something like:

 var indexToSplit = unique.indexOf(',');
 var status = unique.slice(3, indexToSplit - 1);
 var use = unique.slice(2, indexToSplit - 2);
 var pros = unique.slice(0, indexToSplit - 3);
 console.log(pros);

But I figured that is wrong ... any help is appreciated!

what do you mean three arrays? ['on', 'on', 'on'] is one of the array? — Sabrina Luo
– Sabrina Luo, Commented Jan 11, 2017 at 6:14
I think the question is pretty clear... first array would be the com--test kind. Second one the Lsdhfbsdhfbsifashdbaisdq2 strings , and third the 'on' values. — arnoldssss
– arnoldssss, Commented Jan 11, 2017 at 6:16
and quick to make the question and to you guys understand too — arnoldssss
– arnoldssss, Commented Jan 11, 2017 at 6:32

Rajesh Dixit · Accepted Answer · 2017-01-11 06:54:03Z

3

You will have to loop over array and use string.split to get seperate parts.

Once you have seperate parts, you can push them to necessary array;

var d = [ 'com--test,LFutx9mQbTTyRo4A9Re5ksjdnfsI4cKN4q2,on',
  'com--fxtrimester,SEzlksdfMpW3FxkSbzL7eo5MmqkPczCl2,on',
  'com--fxtrimester,LFutx9mQbTTyRoldksfns4A9Re5I4cKN4q2,on'];

var result = [[],[],[]];
var len = 3;
d.forEach(function(str, i){
  var _tmp = str.split(',');
  for (var i = 0; i<len; i++){
    result[i].push(_tmp[i])
  }
})

console.log(result)

A little generic way.

Loop over data and split each string using comma(,)
Loop over split values and check if necessary array exists.
If not, initialise array, but you cannot do p[i] = [] as this will push to first value. You will have to also initialise all previous values. For this, you can use new Array(length). By default, if length is greater than 0, all indexes will be initialise to undefined.
Now push to necessary array. Position will be maintained.

var d = ['com--test,LFutx9mQbTTyRo4A9Re5ksjdnfsI4cKN4q2,on',
  'com--fxtrimester,SEzlksdfMpW3FxkSbzL7eo5MmqkPczCl2,on',
  'com--fxtrimester,LFutx9mQbTTyRoldksfns4A9Re5I4cKN4q2,on,test'
];


var result = d.reduce(function(p, c, index) {
  var _tmp = c.split(',');
  for (var i = 0; i < _tmp.length; i++) {
    // Check if position not defined.
    if (p[i] === undefined)
      // Initialize array and add default (undefined) to all elements before current element
      p[i] = new Array(index);

    p[i].push(_tmp[i])
  }
  return p;
}, [])

console.log(result)

edited Jan 11, 2017 at 6:54

answered Jan 11, 2017 at 6:15

Rajesh Dixit

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2 Comments

Rajesh Dixit Over a year ago

I'm glad I could help! :-)

Rajesh Dixit Over a year ago

@arnoldssss I have added a generic solution that will eliminate need for len=3. Hope it helps.

Steve Bennett · Accepted Answer · 2017-01-11 06:25:10Z

1

With map this becomes:

for positions X out of 0, 1 and 2:
convert each item in the list into an array, and choose the Xth item

var start = [ 'com--test,LFutx9mQbTTyRo4A9Re5ksjdnfsI4cKN4q2,on',
  'com--fxtrimester,SEzlksdfMpW3FxkSbzL7eo5MmqkPczCl2,on',
  'com--fxtrimester,LFutx9mQbTTyRoldksfns4A9Re5I4cKN4q2,on' ]


var out = [0,1,2].map(i => 
  start.map(x => x.split(',')[i]) )
console.log(out)

answered Jan 11, 2017 at 6:25

Steve Bennett

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Comments

Sumit Gupta · Accepted Answer · 2017-01-11 06:42:31Z

1

Since your question does not ask for a more general case, i am safely assuming it for 3 array. We can use forEach function on array below code can be one amongst the possible solutions

var arr1 = [];
var arr2 = [];
var arr3 = [];

var x = ['com--test,LFutx9mQbTTyRo4A9Re5ksjdnfsI4cKN4q2,on', 'com--fxtrimester,SEzlksdfMpW3FxkSbzL7eo5MmqkPczCl2,on', 'com--fxtrimester,LFutx9mQbTTyRoldksfns4A9Re5I4cKN4q2,on']

x.forEach(function(data) {
  var dataArray = data.split(',');
  arr1.push(dataArray[0]);
  arr2.push(dataArray[1]);
  arr3.push(dataArray[2]);
});


console.log(arr1)
console.log(arr2)
console.log(arr3)

edited Jan 11, 2017 at 6:42

answered Jan 11, 2017 at 6:20

Sumit Gupta

445 bronze badges

2 Comments

Rajesh Dixit Over a year ago

Please add explanation. Just adding working code is not good enough.

Sumit Gupta Over a year ago

added :) , will keep in mind from next time . Thanks

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