I know that I can receive args on a command line/shell script like this:
!#/usr/bin/php
<?php
# file name - process.php
print_r($argv);
But what about redirects as follows:
#> ./process.php < input.txt
How do I read the file, and is input.txt a string argument or some type of file pointer already created?
Read from STDIN very similar to C:
<?php
$stdin = fopen('php://stdin', 'r');
// Get the whole file, line by line:
while (($line = fgets($stdin)) !== FALSE) {
...
}
?>
If you'd rather get the whole file contents into one variable, there's a shortcut:
$contents = stream_get_contents(STDIN);
< character referred to (and >) in shell scripting?
Content-type: text/html; charset=UTF-8 - how do I suppress this?
php -h.#!/usr/bin/php -q to suppress this. Wild guess -q stands for quiet ;)Oliver, instead of modifying a user's post, you should post a different answer. Here is what you intended to post:
#!/usr/bin/php -q
<?php
//NOTE the -q switch in hashbang above, silences MIME type output when reading the file!
$stdin = fopen('php://stdin', 'r');
// Get the whole file, line by line:
while (($line = fgets($stdin)) !== FALSE) {
...
}
?>
