Json parsing - JSONArray to JSONObject in JAVA

Question

Item.java

JSONObject json = new JSONObject();
private String value;
private String type;
public String getValue() {
    return value;
}

public void setValue(String value) {
    this.value = value;
}

public String getType() {
    return type;
}

public void setType(String type) {
    this.type = type;
}

public String toString() {
    json.put(value, type);
    return json.toString();
  }

Bean.java

@PostConstruct
public void init() {
    items=new JSONArray();
}


public void add() throws ParseException {   
    items.add(new Item());   
}

public void remove(Item item) {
    items.remove(item);
}

public void save() {
    System.out.println("JsonSchema "+items);
}

public JSONArray getItems() {  
    return items;
}

While retrieving json from Sample.java in Bean.java - I get the output of this format -

[{"id":"number"},{"name":"text"},{"type":"number"}]

I want to convert this to JSONObject of below format using JsonSimple library-

{"id":"number","name":"text","type":"number"} //convert to this format

I am just a beginner. Any help would be appreciated. Thank you in advance.

You made an arrray of objects, but you need 1 object with attributes. — 476rick
– 476rick, Commented Jan 12, 2017 at 7:32
You're not showing what is Sample.java here. If Sample.java holds the responsibility to print a sample Item, you may just get the first item from JSONArray and print the same. — Pavan Kumar
– Pavan Kumar, Commented Jan 12, 2017 at 7:34

Monish Sen · Accepted Answer · 2017-01-12 07:33:00Z

1

You are instantiating with JSONArray. You need to instantiate with JSONObject

items=new JSONObject();

Also you need to use the put method instead of add method

items.put("item1", new item());

See more here

answered Jan 12, 2017 at 7:33

Monish Sen

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Comments

user2458228 · Accepted Answer · 2017-01-12 07:33:54Z

1

The question is not very clear but it seems you dont want an Array . The output you are getting is an Array as you are explicitly serializing into an Array . If you dont want an Array then make a Java POJO to hold all the attributes needed and serialize that. [ ] represents an array in Json

Example what could be done

class POJO {
attribute 1;
attribute 2;
attribute 3;
}

and serialize an Object of this POJO class

answered Jan 12, 2017 at 7:33

user2458228

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