I have this:
typedef struct{
field_1;
field 2;
.....
}student;
typedef struct{
student record[100];
int counter;
}List;
Then I want to add the information for each 'student', for example:
List *p;
gets(p->list[index]->field_1);
but when I compiled the code it threw this:
[Error] base operand of '->' has non-pointer type 'student'
So why can't I point to 'list' and way to access a specific 'record' in 'list'?
Adding code snippet that may help you to read/write the values to the records. Free the pointer to a struct when you're done.
typedef struct{
int age;
int marks;
}student;
typedef struct{
student record[100];
int counter;
}List;
int main()
{
List *p = (List*)malloc(sizeof(List));
p->record[0].age = 15;
p->record[0].marks = 50;
p->counter = 1;
free(p);
return 0;
}
malloc() function. But will calling sizeof(List) create unused counter variables?
The list itself, p, is a pointer, but the value record[100] is not. You would use the -> operator to access values from p then the . operator to access values from the member records.
When you write
`p->record[index]->field_1`
it is expanded as
(*p).(*record[index]).field_1
record[index]`
itself returns a value so there is no sense in adding * operator before that. But you can use
p->(record+index)->field_1
.operator instead of->(the second one)..