python: retry X times if exception met, exit if not

Question

now it works once if connected successfully, but if exception is met, it doesn't retry as I wish, just throwing:

Will retry: [Errno 111] Connection refused

It should return False if all attempts weren't successful and True if at least one returned an answer

Seems there's something complicated with 'while' needed, like

for attempt in range(attempts) and while True

Here's my code:

attempts = 10
for attempt in range(attempts):
   try:
       conn = httplib.HTTPConnection("server:80", timeout=5)
       conn.request("GET","/url")
       r = conn.getresponse()
   except socket.error, serr:
       print("Will retry: %s" % serr)
       conn.close()
   else:
       print("OK")
   finally:
       return False

I tried also:

for attempt in range(attempts):
   while True:
       try:

The same result...

Prateek Dewan · Accepted Answer · 2017-01-18 18:59:56Z

1

Try using a counter and a flag inside a while loop.

def funct():
    flag = False
    counter = 0
    while True:
        counter += 1
        try:
           conn = httplib.HTTPConnection("server:80", timeout=5)
           conn.request("GET","/url")
           r = conn.getresponse()
           flag = True
           break
        except socket.error, serr:
           print("Will retry: %s" % serr)
           conn.close() 
        if counter>9:
           break
    return flag

answered Jan 18, 2017 at 18:59

Prateek Dewan

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1 Comment

GreenLake4964 Over a year ago

hum... i am python newbie, not sure if there is a better way to "encapsulate" the whole "http.conn" steps, so we don't have to use the slightly cumbersome while loop in every func() that i have

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