Convert Functions into lambda functions

Question

i have to convert the following functions into lambda functions, without changing the semantics. How i have to do this?

u = 1

def method1(x):
    def method2(n):
        def method3(m):
            return x + n + m
        def method4():
            global u
            u += 1
        method4()
        return method3
    def method5(y):
        return x + y
    return method2, method5

Edit: Here are my attempts:

method1 x: method2 n: method3 m: x+n+m, method 4 (): method 3, method5 y: x+y, method2 method3

Edit2:

method1 = lambda x:
    method2 = lambda n:
        method3 = lambda m:
         x + n + m
        method4 = lambda :
         global u
         u = u + 1
        #dont know how to integrate "method4() return method3"
    method5 = lambda y:
      x + y
    method2, method5

Looks like you aren't really comfortable with lambda syntax... — ForceBru
– ForceBru, Commented Jan 21, 2017 at 15:29
These are not lambda expressions. Please return to the first point: 1) read about lambdas. — Yevhen Kuzmovych
– Yevhen Kuzmovych, Commented Jan 21, 2017 at 15:29
method4 if not possible to transform to lambdas. And why you want to do this? — Copperfield
– Copperfield, Commented Jan 21, 2017 at 16:04
Basically, you've not covered point 1 enough. Lambdas cannot be multiple lines, nor do I think you can define them within one another — OneCricketeer
– OneCricketeer, Commented Jan 21, 2017 at 16:56

gilch · Accepted Answer · 2020-02-17 05:50:55Z

6

Python's lambdas are a lot more powerful than most people seem to think.

u = 1
(lambda x: (
    (lambda n: [
        (lambda m: x + n + m),
        (lambda: globals().__setitem__('u', globals()['u'] + 1))()
     ][0]),
    (lambda y: x + y)
))

edited Feb 17, 2020 at 5:50

answered May 6, 2018 at 22:44

gilch

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1 Comment

Kwuite Over a year ago

Never seen this before. Impressive writing. Validated your code with python 3.6.7 with much success.

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