I would like to know is there an "easy" way to create two matching arrays inserting some dummy missing value in both arrays so they remain same size and indexes that are the same in both arrays remain the same, so for example:
["A", "B", "C", "D", "E", "F"] and ["B", "C", "E"]
Would be
["A", "B", "C", "D", "E", "F"] and ["N/A", "B", "C", "N/A", "E", "N/A"]
Thanks in advance :-)
One-liner in a list comprehension to do this:
array_1 = ["A", "B", "C", "D", "E", "F"]
array_2 = {"B", "C", "E"}
array_3 = [x if x in array_2 else "N/A" for x in array_1]
print(array_3)
result:
['N/A', 'B', 'C', 'N/A', 'E', 'N/A']
Note that I converted array_2 to a set for quicker lookup.
array_1 = ["A", "B", "C", "D", "E", "F"]
array_2 = ["B", "C", "E"]
array_3 = array_1
for n,x in enumerate(array_3):
if x not in array_2:
array_3[n] = np.nan
print (array_3)
out:
[nan, 'B', 'C', nan, 'E', nan]
a = [1,2,3,4,5] b = [1,3,5] c = [] for el in a: if el in b: c.append (el) else: c.append (0) print (c)