get warning: assignment from incompatible pointer type for using pointer to char array in struct

Question

I get "warning: assignment from incompatible pointer type" when compiling. How can I don't get that warning?

Here is some part of source code:

typedef struct
{
    char id[9];
    char fName[9];    
    char lName[9];
    int finalExam;
    int midTerm;
    float quiz1;
    float quiz2;
    float quiz3;
    float totalMark;
} Student;

....
....
....

pointAt = students; // initialize pointer
            float* topMark;
            char* topLname;
            char* topId;
            topMark = &(*pointAt).totalMark;
            topLname = &(*pointAt).lName;
            topId = &(*pointAt).id;
            printf("top guy : %s\n", topLname);
            pointAt += 1;

I get that warning at:

topLname = &(*pointAt).lName;
    topId = &(*pointAt).id;

these 2 lines causes that warning, because it points to char array. How can I fix this?

dbush · Accepted Answer · 2017-01-26 18:42:59Z

2

&(*pointAt).lName and &(*pointAt).id are of type char (*)[9], while the variables these values are being assigned to are of type char *, hence the mismatch.

Get rid of the & operator to get an expression of the char [9] which will decay to a char *. While you're at it, use the -> operator to reference the member of a struct pointer:

topLname = pointAt->lName;
topId = pointAt->id;

answered Jan 26, 2017 at 18:42

dbush

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