How to remove word "null" from string in ActionScripts3

Question

I have code for convert each 2 numbers to a specific character, this code works, but output is with an unwanted word "null". I want to remove it. I can't identify which part of code is wrong.

var encoded_numbers:String = "102030";
var sub:String;
var decode_string:String;

for (var i2:int = 0; i2 < encoded_numbers.length; i2 += 2) 
{
    sub = encoded_numbers.charAt(i2) + encoded_numbers.charAt(i2 + 1);
    //trace(sub);

    switch(sub) 
   { 
    case "10": 
        decode_string += "A";
        break; 
    case "20": 
        decode_string += "B";
        break; 
    case "30": 
        decode_string += "C";
        break; 

   }

}
trace(decode_string);//convert

Output string:

nullABC

Nbooo · Accepted Answer · 2017-01-27 11:53:32Z

5

Initial value of your decode_string is null. Just assign the initial value as follows:

var decodeString:String = "";

answered Jan 27, 2017 at 11:53

Nbooo

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1 Comment

Mohammad Samir Over a year ago

Thanks for your simple answer.

VC.One · Accepted Answer · 2017-01-27 12:06:53Z

"...but output is with an unwanted word "null". I want to remove it. I can't identify which part of code is wrong."

When you say : var decode_string:String; you've declared a variable but it has no value so by default it gives result of "null". The problem later is when you use += operator to further append your ABC letters, the final string has now become nullABC.

To fix :

Make your strings empty/blank (but never value-less) by using String = "";...

var encoded_numbers:String = "102030";
var sub:String = "";
var decode_string:String = "";

Also consider substr for extracting parts of texts (instead of charAt)..

for (var i2:int = 0; i2 < encoded_numbers.length; i2 += 2) 
{
    sub = encoded_numbers.substr(i2, 2); //gets 2 letters from position of i2
    //trace(sub);

    switch(sub) 
    { 
        case "10": 
            decode_string += "A";
            break; 
        case "20": 
            decode_string += "B";
            break; 
        case "30": 
            decode_string += "C";
            break; 

    }

}
trace(decode_string);//convert

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