Can't escape and parse characters in Python string formatting

Question

Found this link already:

How can I print literal curly-brace characters in python string and also use .format on it?

Didn't quite get me to where I need to go as I have some crazy characters in this string. I need to be able to keep the outer curly brackets (in the line starting with ':9502...'), while being able to format the {0}.

    try:
    filtered_df['Path'] = \
        filtered_df['Path'].apply(lambda x: '<a href="http://'
                                            + host
                                            + ':9502/analytic/saw.dll?catalog#{"location"%3A"{0}"}" target="_blank">{1}</a>'.format(urllib.quote(x, safe=''), x))

So as you can see, I'm trying to simply change some of my column values in a pandas dataframe to an html link. The issue is the required formatting of the destination link (the portion detailed below):

catalog#{"location"%3A"{0}"}" target="_blank">{1}</a>'.format(urllib.quote(x, safe=''), x))

Suffice to say it's pretty crazy and that's how it has to look to get to where I need to go. The issue is is that it doesn't allow the app to execute as written, so the problem, at least I'm guessing, is that I need to do something about those curly brackets and maybe some of the quotes?

piRSquared · Accepted Answer · 2017-01-31 06:12:32Z

3

You escape the curly braces by doubling them up.

'outside{{inside {0}}}'.format('stuff')

'outsid{inside stuff}'

answered Jan 31, 2017 at 6:12

piRSquared

296k68 gold badges509 silver badges654 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Can't escape and parse characters in Python string formatting

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related