Regex multiple filters

Question

Need help with a regex to select multiple lines. From what I have so far it works until I put the last regex in. Once I do that, it skips over the middle one. Passwords have been removed for security purposes.

My Goals

Select all lines beginning at Current configuration ending at version, "or the ! right before it"
Select all lines with "secret"
Select all lines with "password"

My Regex

(?s)Current configuration (.*)NVRAM|secret 5 +(\S+)|password 7 +(\S+)

EDIT: took about spaces before and after the | and it seems to highlight what i want. It doesn't do the entire line though.

Test Data

Building configuration...

Current configuration : 45617 bytes
!
! Last configuration change at 00:22:36 UTC Sun Jan 22 2017 by user
! NVRAM config last updated at 00:22:43 UTC Sun Jan 22 2017 by user
!
version 15.0
no service pad
!
no logging console
enable secret 5 ***encrypted password***
!
username admin privilege 15 password 7 ***encrypted password***
username sadmin privilege 15 secret 5 ***encrypted password***
aaa new-model
!
ip ftp username ***encrypted password***
ip ftp password 7 ***encrypted password***
ip ssh version 2
!
line con 0
 password 7 ***encrypted password***
 login authentication maint
line vty 0 4
 password 7 ***encrypted password***
 length 0
 transport input ssh
line vty 5 15
 password 7 ***encrypted password***
 transport input ssh
!

Desired Result:

Building configuration...

!
version 15.0
no service pad
!
no logging console
enable 
!
username admin privilege 15 
username gisadmin privilege 15 
aaa new-model
!
ip ftp username cfgftp
ip ftp 
ip ssh version 2
!
line con 0

 login authentication maint
line vty 0 4

 length 0
 transport input ssh
line vty 5 15

 transport input ssh
!

are you using global? it seems to be working how you have it if you use the global flag regex101.com/r/TyT1Mp/1 — maraaaaaaaa
– maraaaaaaaa, Commented Jan 31, 2017 at 14:45
@maksymiuk I removed the spaces before the | and it seems to be selecting what i need now. do you know how to use re.sub(). I'm basically trying to use this regex to then replace it with an empty string " ". — NineTail
– NineTail, Commented Jan 31, 2017 at 15:04

NineTail · Accepted Answer · 2017-01-31 15:24:34Z

1

This Should Work.

REGEXP:

((?:\bCurrent configuration)(?:.*\n?){6})$|((?:\bsecret)(?:.)+$)|((?:\bpassword\s)(?:.)+$)

INPUT:

Building configuration...

Current configuration : 45617 bytes
!
! Last configuration change at 00:22:36 UTC Sun Jan 22 2017 by user
! NVRAM config last updated at 00:22:43 UTC Sun Jan 22 2017 by user
!
version 15.0
no service pad
!
no logging console
enable secret 5 ***encrypted password***
!
username admin privilege 15 password 7 ***encrypted password***
username sadmin privilege 15 secret 5 ***encrypted password***
aaa new-model
!
ip ftp username ***encrypted password***
ip ftp password 7 ***encrypted password***
ip ssh version 2
!
line con 0
 password 7 ***encrypted password***
 login authentication maint
line vty 0 4
 password 7 ***encrypted password***
 length 0
 transport input ssh
line vty 5 15
 password 7 ***encrypted password***
 transport input ssh
!

OUTPUT:

Group: $1:

Current configuration : 45617 bytes
!
! Last configuration change at 00:22:36 UTC Sun Jan 22 2017 by user
! NVRAM config last updated at 00:22:43 UTC Sun Jan 22 2017 by user
!
version 15.0

GROUP $2:

enable secret 5 ***encrypted password***

GROUP $3:

password 7 ***encrypted password***
password 7 ***encrypted password***
password 7 ***encrypted password***
password 7 ***encrypted password***
password 7 ***encrypted password***

See: https://regex101.com/r/NOrndn/1

Test Python Code: http://ideone.com/UyjT38

edited Jan 31, 2017 at 15:24

NineTail

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answered Jan 31, 2017 at 15:02

Eduardo Lynch Araya

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1 Comment

NineTail Over a year ago

I i modified the regex to just have secret instead of enable secret and this does exactly what i want. Thank you.

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