How do I do this in C++?
I know how to create a pointer to a function but that requires having a name for that pointer.
What I actually need is to somehow create a pointer without naming it.
I know the syntax for array of ptr to functions. This might help:
out-type (*ptr[size])(parameters...)
You should really use a boost/std::function<out_type(parameters)> instead. However, to answer the question at hand, you could use a typedef
typedef out_type(*typedef_name)(param_types);
std::vector<typedef_name> vec;
Or you can just supply the vector with the type directly.
std::vector<out_type(*)(param_types)> vec;
