creating json output using php

Question

I have this so far :

if (is_request_var('requestor') == 'PPA'){
   $dataJson[][]  = array("status" => "success","value" => $fetchValue ,"postcode" => $fetchPostCode,"params"=>""); 

   $notice = $dataJson;
}

I want to get (refer below) from PHP how do i arrange my PHP array code

jQuery191013316784294951245_1485527378760([
  {
    "value": "\u003cstrong\u003eNAIROBI\u003c/strong\u003e KENYATTA AVENUE, GENERAL POST OFFICE, 00100",
    "postcode": "00100"
  },
  {
    "value": "\u003cstrong\u003eNAIROBI\u003c/strong\u003e HAILE SALASSIE AVENUE, CITY SQUARE, QLD, 00200",
    "postcode": "00200"
  }
])

You should use json_encode function: json_encode(array("status" =>..... and return it. — rescobar
– rescobar, Commented Feb 4, 2017 at 12:41
@rescobar would it return the way i want my json data formatted ? — Philip W Marsh
– Philip W Marsh, Commented Feb 4, 2017 at 12:43
@ Philip W Mars , It will return the JSON representation of a value, in this case of an array. — rescobar
– rescobar, Commented Feb 4, 2017 at 12:50

rescobar · Accepted Answer · 2017-02-04 12:47:26Z

1

Try this:

$dataJson = array("value" => $fetchValue, "postcode" => $fetchPostCode);
$notice = json_encode($dataJson);
echo $notice;

Returns a string containing the JSON representation of value.

http://php.net/manual/en/function.json-encode.php

answered Feb 4, 2017 at 12:47

rescobar

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