Parse HTML using Python

Question

I am trying to parse HTML using Beautiful SOAP (Python Library). Does anyone know how to parse below HTML using Beautiful SOAP?

  <span class="passingAlert bar">
     <span class="fold-buttons">
         <a href="#" onclick="fold();">Fold</a> | 
         <a href="#" onclick="unfold();">Unfold</a>
     </span>149 specs, 0 failed, 0 pending
  </span>

I need to get 149 specs, 0 failed, 0 pending from HTML.

to parse you need soup = BeautifulSoap(your_html, 'html.parser'). After that you have to only "search". — furas
– furas, Commented Feb 5, 2017 at 23:07

furas · Accepted Answer · 2017-02-05 23:11:31Z

1

html = '''<span class="passingAlert bar">
     <span class="fold-buttons">
         <a href="#" onclick="fold();">Fold</a> | 
         <a href="#" onclick="unfold();">Unfold</a>
     </span>149 specs, 0 failed, 0 pending
  </span>'''

from bs4 import BeautifulSoup

soup = BeautifulSoup(html, 'html.parser')

# get <span class="fold-buttons">
c = soup.find(class_="fold-buttons")

# get element after `span`
print( c.nextSibling.strip() )

answered Feb 5, 2017 at 23:11

furas

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