Converting HTML escape sequence to Java

Question

I am receiving a string using REST APIs.

JSONObject obj = new JSONObject(output);
JSONArray contacts = obj.getJSONArray("results");
JSONObject result = contacts.getJSONObject(0);
..
String brandName = result.getString("productName");

In some cases productName comes as Dri-FIT™ Element Half Zip.

I want to show it as "Dri-FIT™ Element Half Zip" in Android, but it shows up in the TextView as Dri-FIT™ Element Half Zip.

How can I convert the HTML escape sequence to a valid Java escape sequence so that I can view it?

Can you try the answers posted in stackoverflow.com/questions/13700333/… — GrabNewTech
– GrabNewTech, Commented Feb 6, 2017 at 2:20
@GrabNewTech, no that answers for elements where I have \uHex number. But that is what I want. right now I am getting it in HTML form. — Anindya Dutta
– Anindya Dutta, Commented Feb 6, 2017 at 2:25

Harry T. · Accepted Answer · 2017-02-06 02:25:37Z

1

You can try this. I think this is the best way to show your special symbol.

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
            tv.setText(Html.fromHtml("Dri-FIT&#8482; Element Half Zip", Html.FROM_HTML_MODE_COMPACT));
        }else{
            tv.setText(Html.fromHtml("Dri-FIT&#8482; Element Half Zip"));
        }

answered Feb 6, 2017 at 2:25

Harry T.

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1 Comment

Anindya Dutta Over a year ago

Thanks! I had used this sometime before, just couldn't remember that the fromHtml method existed.

Richard LIANG · Accepted Answer · 2017-02-06 02:12:06Z

0

Please replace &#8482 to \u2122 (2122 is hex for 8482)

answered Feb 6, 2017 at 2:12

Richard LIANG

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2 Comments

Harry T. Over a year ago

I think this is not what he wants. He want to change all symbols possible, not exactly this ™.

Anindya Dutta Over a year ago

Yeah. in general whenever I get a symbol

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