Change to directory using variable name

Question

I've written a script to search for a shape file (.shp), I want to change to that directory once found: Here's what I have

 FOR /F %%X IN ('DIR /S /B *.shp') DO SET shapefolder=%%~DPNX
 IF DEFINED shapefolder (
 ECHO %shapefolder%
 CD /d shapefolder REM doesn't work
 ) ELSE (
 ECHO File not found
 )

What am I missing?

SomethingDark · Accepted Answer · 2017-02-07 13:03:37Z

1

Two things are wrong with your code. The first, as Oliver already pointed out, is that cd /d shapefolder should be cd /d %shapefolder% so that you're calling the actual variable.

The other thing is that SET shapefolder=%%~DPNX should beSET shapefolder=%%~DPX instead.

This is because the N refers to the filename of the file it finds, so if you have a square.shp, your code currently will look for C:\files\shapes\square instead of C:\files\shapes\ like it's supposed to.

edited Feb 7, 2017 at 13:03

answered Feb 7, 2017 at 12:37

SomethingDark

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Mr Mystery Guest Over a year ago

cd \d %shapefolder% ?? Are you sure you don't mean cd '/d %shapefolder%

Oliver · Accepted Answer · 2017-02-07 12:33:32Z

0

Just add the percent sign to your variable in the cd command:

CD /d %shapefolder%

answered Feb 7, 2017 at 12:33

Oliver

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