I have files like:
abc.json
xyz.json
pdf.json
I would like to get the result like this without "json" extension:
somearray=(abc, xyz, pdf)
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1Commas in array doesn't really make sense. What is your idea behind having it? Did you try anything to solve the problem?Inian– Inian2017-02-09 06:39:15 +00:00Commented Feb 9, 2017 at 6:39
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2 Answers
You can get your files into an array with globbing, then remove the extensions with parameter expansion:
$ arr=(*.json)
$ declare -p arr
declare -a arr='([0]="abc.json" [1]="pdf.json" [2]="xyz.json")'
$ arr=("${arr[@]%.json}")
$ declare -p arr
declare -a arr='([0]="abc" [1]="pdf" [2]="xyz")'
Comments
You can do it simply with this:
some_array=( $(ls | sed 's/.json$//') )
Or, if you are only looking for .json files, then:
some_array=( $(ls | grep '.json$' | sed 's/.json$//') )
The method above is not safe if you have any files that have white space or wildcard (*) in them.
If you are using Bash, then you can use parameter expansion to take the extension out. And this approach is more robust than the earlier ones - it handles files with white spaces or wildcard gracefully:
declare -a some_array
for file in *.json; do
some_array+=( "${file%.json}" )
done
See these posts:
6 Comments
Inian
There is nothing wrong with adding quotes around parameter expansion, in-fact it is most efficient.
codeforester
In fact, it is required for handling files with spaces. Corrected, thanks for noticing it, @Inian.
Inian
You can do far better than parsing output of
ls and using grep/sed back to back makes it worse. There is every chance of word-splitting in the first two cases. Better don't recommend the first two approaches.
ckruczek
@Inian: So then please post a improved version, so that others can learn from it. Just complaining is not a high-quality comment.
codeforester
I updated the answer based on @Inian's comment. It is good to see his answer as well.
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