Indexing when working with cell array

Question

I have 3x2 cell array called signals. All cells contain a 8x6xN array full of integers. I am trying to move down every row by one row and overwrite the first row with NaNs. Howevery, I am struggling with the correct syntax regarding indexing. I am able to manipulate one particular cell like this:

signals{1,1}(2:end, :) = signals{1,1}(1:end-1, :);
signals{1,1}(1,:) = NaN;

How can I apply this manipulation to the whole cell array? I am basically looking for something like this:

signals{:}(2:end, :) = signals{:}(1:end-1, :);

Suever · Accepted Answer · 2017-02-09 13:50:33Z

1

You need to loop through each element in the cell array and perform the operation on each of these elements.

for k = 1:numel(signals)
    signals{k}(2:end, :) = signals{k}(1:end-1, :);
    signals{k}(1,:) = NaN;
end

answered Feb 9, 2017 at 13:50

Suever

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2 Comments

Andi Over a year ago

Is there a way to solve that problem without using a loop. I am looking for the most efficient way in terms of speed as the signals matrix may become quite large.

Suever Over a year ago

@Andi No. Thanks to JIT acceleration, the performance penalty for using a loop such as this is minimal. Also, if you really want performance, then I would use a multi-dimensional array rather than a cell array if possible.

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