Hide html when included inside php if condition

Question

I would like to present some php with the help of html formatting.

My purpose is to print:

Life status: dead (1850 in New-York)

or (if not dead):

Life status: alive

The place and date should only by printed if the condition $life_status is set to "dead".

The following code works for the dead situation but not for the alive one.

<h3>Title</h3>
<ul>
    <li>Life status: <?php echo $life_status;?>
    <?php if($life_status="dead"):?>
        (<?php echo $date_death; ?> in <?php echo $place_death; ?>).
       </li>
    <?php endif; ?>
</ul>

For the alive sitation, I obtain:

Life status: Alive ( in ).

How can I applied the php condition on "( in)."?

You are opening your <li> tag but only closing it if your if evaluates to TRUE. You should move the </li> to after your endif; so that the tag always closes. — AmericanUmlaut
– AmericanUmlaut, Commented Feb 9, 2017 at 20:11

coderodour · Accepted Answer · 2017-02-09 20:15:23Z

2

Your operator for checking if $life_status is dead is wrong. It is a single equal and should be double. Code below reflects these changes and implements what @AmericanUmlaut correctly suggested in the comment above to make your html actually valid.

<h3>Title</h3>
<ul>
    <li>Life status: <?php echo $life_status;?>
    <?php if($life_status == "dead"):?>  // This maybe the issue, wrong operator used to evaluate.
        (<?php echo $date_death; ?> in <?php echo $place_death; ?>).
    <?php endif; ?>
    </li>
</ul>

answered Feb 9, 2017 at 20:15

coderodour

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Comments

AmericanUmlaut · Accepted Answer · 2017-02-09 20:13:46Z

1

You are using the wrong operator. = is assignment, == tests equality.

<h3>Title</h3>
<ul>
    <li>Life status: <?php echo $life_status;?>
    <?php if($life_status=="dead"):?> // == here instead of =
        (<?php echo $date_death; ?> in <?php echo $place_death; ?>).
    <?php endif; ?>
    </li>
</ul>

(Note that I also moved the outside of the if block to address the issue I noted in my comment.)

answered Feb 9, 2017 at 20:13

AmericanUmlaut

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2 Comments

ppr Over a year ago

Thanks. I did the modifications. However, with two =, the condition is never activated. I obtain Life status: alive or Life status: dead only. It is strange because echo $life_status prints "dead" or "alive". Any idea?

ppr Over a year ago

Ok I fix it. The "dead" was a link and therefire didn't activate the condition.

Sarmad Agha - SA Techy · Accepted Answer · 2017-02-09 20:59:24Z

In Php strings are not compared directly and may not give the results which are intended. Therefore, using strcmp(); function will do the work. It returns 0 when 2 strings compared are equal and is a case sensitive function.

In your case:

<h3>Title</h3>
<ul>
    <li>
        Life status: <?php 
            echo ( !strcmp($life_status,"dead") ) ? 'Dead ( '.$date_death.' in '.$place_death.' ).' : 'Alive' ;
       ?>
    </li>
</ul>

I have used the Php Ternary operator known as Shorthand if/else. The ! will reverse the 0 to 1 if its true to show the Dead output and else will show the Alive output.

Php Ternary : http://php.net/manual/en/language.operators.comparison.php

Php strcmp() : http://php.net/manual/en/function.strcmp.php

I hope it helps :)

Regards, SA

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