I can't get to have the variables in an expect loop written:
#!/bin/bash
expect -c "
set var1 10
puts {$var1}
puts $expect_out({$var1})
foreach name { bob jim jacobo henric } {
puts {hello $name $var1}
}"
my output is:
# ./test
({})
hello
hello
hello
hello
So basically it's not expanding any variable. Any idea?
You should quote with ', not "! This should get the job done:
#!/bin/bash
expect -c '
set var1 10
puts "$var1"
send_user "Confirm? (Y/n): "
expect_user -re "(.*)\n"
set var1 $expect_out(1,string)
foreach name { bob jim jacobo henric } {
puts "hello $name $var1"
}
'
Output:
10
Confirm? (Y/n): Y
hello bob Y
hello jim Y
hello jacobo Y
hello henric Y
Thanks a lot, it worked as a charm. But it has some issues when the array elements are passed via parameter like this:
function a {
names=$1
expect -c '
foreach name { $names } {
puts "$name"
}
'
}
It just prints:
$names
foreach name { ' "$names" ' } {you mean that any variable must be wrap around by single and double quotes?
' "$variable" '
ok I decided to put the expect code in a separate script test.ex:
set interfaces [lindex $argv 0]
foreach int { $var} {
puts $int
}
When I call the expect it does not cycle over the strings elements:
test.ex "string1 string2"
as it just prints:
$var
It is just ignoring the variable content, and it handles the variable as a string itself without expanding it, is there a way to get it work?
I figured it out! Just needed to remove the curly brackets {} around the variable that need to be looped over:
set interfaces [lindex $argv 0]
foreach int $var {
puts $int
}