Passing anonymous function as callback in Javascript

Question

Is there a way to pass anonymous function as a custom callback function in Javascript? I have this code:

function notifyme(msg){
    console.log(msg)
}

notifyme("msg", function(){
    //do some custom redirect logic    
});

I am trying the above code and it's executing notifyme function, but not going further with redirect code. I know I can pass a function name as a callback, but I don't have a specific function that I can pass. This is why they invented the anonymous function I guess.

It'd be really nice if there was a way to do that.

The question is not about optional callback, it's about passing anonymous function call back — Lamar
– Lamar, Commented Feb 13, 2017 at 12:45

ricky · Accepted Answer · 2017-02-13 12:04:05Z

19

Your code pattern should be like

function notifyme(msg,callback){
    console.log(msg);
    // Do your stuff here
    if(callback){
      callback();
    }
}

notifyme("msg", function(){
    //do some custom redirect logic    
});

answered Feb 13, 2017 at 12:04

ricky

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Comments

Liam · Accepted Answer · 2021-05-24 07:49:10Z

6

You can call your function simply by invoking it ():

function notifyme(msg, myFunc){
        console.log(msg);
        myFunc();
}
    
notifyme("msg", () => {
        console.log("function called");   
});

myFunc in the above is a variable pointing at your function. By invoking it, () you call the function that the variable (myFunc) points at.

This answer doesn't go into details about the custom redirect logic. Because I don't know what this does.

edited May 24, 2021 at 7:49

answered Feb 13, 2017 at 12:03

Liam

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Comments

Lew · Accepted Answer · 2017-02-13 12:03:41Z

4

You need to call your callback!

function notifyme(msg, callback){
    console.log(msg);
    callback();
}

notifyme("msg", function(){
//do some custom redirect logic    
});

answered Feb 13, 2017 at 12:03

Lew

1,2788 silver badges13 bronze badges

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