We have a script, with a return code. For example
#!/bin/bash
exit 42
which is works fine:
$ ./script ; echo $?
42
but if i go:
$ bash << EOF
./script ; echo $?
EOF
0
so it prints 0, while one would expect it to still print 42
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1You don't have any pipes here, you're using bash to process a heredocEric Renouf– Eric Renouf2017-02-13 14:47:38 +00:00Commented Feb 13, 2017 at 14:47
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1 Answer
Your $? is being expanded before executing the script. If you don't want your variables to expand in the heredoc (not a pipe) put single quotes around the name:
bash <<'EOF'
./script; echo $?
EOF
That wil prevent $? from being expanded while passing the string to the new bash command. It will, instead, be evaluated in the string which is what you seem to be going for.